Physics Homework problem: Dielectrics

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Homework Help Overview

The discussion revolves around a problem involving a capacitor with an air gap and the introduction of a dielectric material (mica). Participants explore how the dielectric affects the charge flow from a connected battery.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the initial charge flow when the capacitor is filled with air and how the introduction of mica as a dielectric alters the capacitance. Questions arise regarding the specifications of the capacitor and the effects of the dielectric on the system.

Discussion Status

The discussion includes attempts to clarify the initial conditions of the problem and the implications of using a dielectric. Some participants have provided equations related to capacitance and charge, while others express confusion about the capacitor's specifications and the impact of the dielectric.

Contextual Notes

There is uncertainty regarding the exact type of the capacitor (μF or nF) and how the dielectric constant influences the calculations. One participant indicates they have resolved their confusion independently, suggesting a shift in the discussion's focus.

Jscrub
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I cannot figure out this problem...can someone help me?

A 3500 air-gap capacitor is connected to a 32 battery.

If a piece of mica fills the space between the plates, how much charge will flow from the battery?


Express your answer using two significant figures.
 
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Welcome to PF!

Hi Jscrub! Welcome to PF! :wink:

First, how much charge will flow from the battery when the gap is just air?

Second, what equations do you know about how a dielectric affects a field or a capacitor? :smile:
 
c= KCo

c=Q/V

Q Air = 1.12E-4
 
v= 32 V

K(mica) = 7

K (air) = 1.0006

so, Co= 1.12E-4
 
Jscrub said:
A 3500 air-gap capacitor is connected to a 32 battery.

What is a 3500 air-gap capacitor?

Is that a 3500μf capacitor or 3500nf?

What is the effect of the dielectric on the capacitance?

I don't follow your conclusion
so, Co= 1.12E-4

Haven't you added a dielectric to your capacitor?
 
The above was not a conclusion..it was just a reply to the previous person...

Co = 3500E-9...

But it is fine..I don't need anymore help...I figured it out...

Thanks
 

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