Recent content by JustDerek

Managed to get there myself eventually but thanks for the intended help

Homework Statement I've been given a problem with pulleys which I have attached to this post. I've derived the equations shown in the post but I'll also write them below. What I'm struggling with is how to combine them. Homework Equations ##l_1=S_a+2S_c## ##l_2=S_d+(S_d-S_c)##...

Ah yeah. Good point. I won't try and input anymore I've already been wrong once

I'm not 100% sure as I'm just learning this stuff myself. But I think you can work out the velocity to the bottom of the window by just doing ##v_1=d/t## calling this velocity ##v_1## then put this in as an initial velocity in your ##v=v_0+at## to find out your v over the two seconds. Then use...

I'm not sure as I'm only just learning this stuff myself though it appears I'm a couple of weeks behind you but wouldn't it be worth finding the mass flow rate? Sorry if that's wrong.

That's OK. The intention to help was appreciated

Thanks for all your help. I'll see what I can do from here. You've been a saint I'd give you +100 likes if I could

Never done that before but I'll look into it. Won't that give multiple values for t?

Which is get ##524=0.01t^3+5t## which believe it or not I've had worked out for two days. What I don't get is how to isolate t from this

So I make ##a=0 s=524 and V_0=5## and try to solve t for this?

Wouldn't that make c=0 at the start point?

You right I did integrate it wrong it's ##5t## and not ##2.5t^2##

ok now my mind is just gone, I'm going to leave it for a while and come back to it another time

also i know this gives ##524=0.01^3+2.5t^2+c##

I've integrated twice. I got ##v=0.03t^2+5t## and then integrated again to get ##s=0.01^3+2.5t^2+c## but even here I'm unsure how to isolate the t's because they have different powers and values attached to them