Recent content by kevina

No, I'm pretty sure v = ((m+M)/m)*sqrt(2gL[1 - cos(theta)]) is correct.

Yes! I remember seeing that link once before. I was looking for it but couldn't find it. Thanks Doc Al. :)

How will it change the result? Because (10000+6)/10000 and (10000+12)/10000 is still the same as when it was in kg.

Ok, am I on the right track? I've got these two equations: (v_0)_9=((10 + .006)/10)*sqrt(2*9.8*L[1 - cos 4.3]) (v_0)_44=((10 + .012)/10)*sqrt(2*9.8*L[1 - cos 10.1]) I'm solving for velocity. When I find (v_0)_9 and (v_0)_44, I can just divide them to get the answer. I got .70. Is it a...

Can someone explain to me the vector nature of momentum in a case where two objects collide and stick together?

Ahh.. I see.. I wasn't using the right equation. Thanks for the help Doc Al and hagar852. :)

I got .443 for the 9mm and .633 for the .44-caliber. Is this right? The numbers look weird.

Oh, my mistake. That's a typo right there. I editted it already. Let me try to solve it.

The Question In a ballistic pendulum an object of mass m is fired with an initial speed v_0 at a pendulum bob. The bob has a mass M, which is suspended by a rod of length L and negligible mass. After the collision, the pendulum and object stick together and swing to a maximum angular...

The Question: (1) You are standing on a sheet of ice that covers a parking lot; there is negligible friction between your feet and the ice. A friend throws you a 0.400 kg ball that is traveling horizontally at 10.2 m/s. Your mass is 73.4 kg. (a) If you catch the ball, with what speed do...