Recent content by keximaze

That's what I did. I cut the cable where the lowest point is located, took the moment about a, and got ya = waxa2 / 2To for the left side and yb = wbxb2 / 2To for the right side and when I took the moment about A for the entire body, I obtained another equation. k = wb / (2*To)...

Thanks for the hint...But I do not understand how to get these two equations :cry:

Hello. Yep, I meant xb I know that I have to exploit the relations between xa, xb, ya, and yb...But I don't know what you mean by "you know kxa2 and kxb2" Thanks.

[SIZE="3"]Please help PROBLEM Cable AB supports a load distributed uniformly along the horizontal as shown. The lowest portion of the cable is located at a distance a = 3.6m below support A, and support B is located a distance b = na above A. -> Determine the maximum tension in the cable as...

Please explain what you mean by "one must be very careful to understand what is known and what is not known"...am I going on the right track or did I make a mistake on the first part? More hints pleaseeeee.

1. Three guy wires hold a pole BO as shown. The resultant R of the forces due to the three wires has a magnitude of 1000-N and is directed on the pole BO. Force F2 and F3 have a magnitude of 400-N and 500-N, respectively. The distance from point A to point D is 5-m. Find the tension in cable...