Recent content by Kidphysics

Darn, guess it was feasible lol!

Don't think anything like this has been posted, and this isn't HW, just curiosity from someone in OR from FL. I'd like someone to play along with me here either help me out or rip me to pierces. A few simple things: how would I calculate heat generation needed to make a person comfortable in...

Thank you for the reply I think my main misunderstanding is this: does the fission neutron escape one fuel cladding and enter into the cladding of another fuel assembly?

Hello there, I appreciate the response. I would say my profile is slightly above mediocure which is why I listed all of my stats. What do you think of where I stand? Perhaps my writing and letters will help in the acceptance. Also I know that reading these books and beccoming fluent in the...

In case of a meltdown wouldn't large amounts of boron dust dumped over the core eat up all the free neutrons?

Homework Statement Having trouble understanding why it is that inside a waveguide sides x=a,y=b propagating in z, subject to b.c. E parallel= 0 and Bperp=0... that for TE Bz=Bcos(pinx/a)cos(pimy/b) but for TM Ez=Esin(pinx/a)sin(pimy/a)? Homework Equations E parallel= 0 and Bperp=0 For...

No your answer was perfect, I responded but re-read your post and it answered the question I thought I had. Not knowing how to delete my post I just edited my answered follow up question to "id like to delete this post" the answer was great, I thank you

i want to delete this post

interesting, thanks; do you recommenced a place?

Homework Statement http://whoisntdavidrinaldi.com/physics/split.png Homework Equations AxB=C The Attempt at a Solution I understand that the beam splits, but why does it not split horizontally? If I hold my index finger to the page with my middle finger up then my thumb is...

Or some naturally occurring material what would I use. I'd like the strongest constant uniform magnetic field possible. Is there some sheet of material I can use?

yes it says this must be the case. For light. I guess this means E.B=0 for light but it is not necessary for them to be orthogonal, but this does not mean it is light if the first condition is not met?

ah, for it to be light must they be orthogonal?

Homework Statement E . B =0 Homework Equations ∇xE=B The Attempt at a Solution I know AxB=C implies both A and B are orthogonal to C but does the same thing ring true for the Del cross something? In any case, is there a nice simple proof for the problem stated? This is not HW...

what did you score on your gre's and what is your gpa?