Recent content by KingKendrick

Homework Statement Integral of f(x)dx from a to b~ S(n) = f(x0) + 4(x1) +2(x2) + 4(x3) + ... 2(xn-2) + 4(xn-1) + f(xn))(Δx/3) You can use the formula for Simpson's Rule given above, but here is a better way. If you already have the Trapezoid Rule approximations T(2n) and T(n), the next...

Yes that makes sense. But the statement that was posted earlier. x=p+r=(a+b)/2+r a+b−x=p−r How would I apply this?

How exactly did you get the first part there? Is it saying f(x) = f(p+r) = f((a+b/2)+r)? and f(a+b-x) = f(p-r)? Sorry for all the questions but I need this in about 12 hours and I'm kind of panicking.

Anyone? Still having trouble. :(

Ok! Thanks for that. So pretty much I converted the -> 2f((a+b)/2) into 2f(p), as in the last question. I'm still having trouble converting the f(x) into f(p+r) and f(a+b-x) into f(p-r). What would be the r? I understand the equation, but the conversion is still lost, I feel like I'm not...

Would the f(p) be the f(a+b)/2 in this case? Sorry, but I'm having a bit of of trouble understanding the question as a whole.

Homework Statement This is the second part of a question I asked earlier. I tried to figure it out but was having trouble even with 4 of my peers. PART 1 (SOLVED) A function f is said to symmetric about a point (p,q) if whenever the point (p-x, q-y) is on the graph of f, then the point...

I guess I was thinking it was going to be a tough problem requiring integrals, I actually had the answer at one point and thought it was too obvious and discarded it. Thanks for all your help!

Haha. I haven't done math for 2 semesters so I'm a bit rusty. So I revised it to this f(p+x) + f(p-x) = 2f(p) f(p)= q f(p+x) = q+y f(p-x) = q-y f(p+x) + f(p-x) = (q+y) + (q-y) f(p+x) + f(p-x) = 2q we know f(p) = q so substituting this in the 2q we get f(p+x) + f(p-x) =2f(p)

Ok, I made progress but I don't know if I am answering the question or if I am doing something completely random. Prove: f(p+x) + f(p-x) = 2f(p) If we can assume f(p)=q f(p+x)=q+y f(p-x)=q-y then f(p+y) + f(p-y) = 2q + 0 f(p) + f(y) + f(p) - f(y) = 2q 2f(p) = 2q We know f(p) = q so...

Could you be a bit more specific or rephrase what you said please? I wrote f(p)=q f(p+x)=q+x f(p-x)=q-x and I'm still struggling to figure out what to do next. Would I have to make them equal to each other? What exactly did you mean when you said "eliminate the q"? Thanks for your help.

Homework Statement A function f is said to symmetric about a point (p,q) if whenever the point (p-x, q-y) is on the graph of f, then the point (p + x, q - y) is also on the graph. Said differently, f is symmetric about a point (p,q) if the line through the points (p,q) and (p+x, q+y) on the...