Recent content by [KNIGHT]

Homework Statement An astronomical telescope is constructed using 2 convex lenses. The objective lens is of focal length 40cm and eyepiece lens is of focal length 10cm. Let d be the distance between the 2 lenses. Draw ray diagrams for the following situations. 1.When d=50cm 2.When d>50cm...

What about the method to solve the 1st first? Is it correct?

Here is the way i did it considered 1 & 2 as a parallel pair and found their resistance and added it in series with 4. (group 1) Then i added 7 & 5 in series and considered it as group 2. The final answer was obtained by adding group 1 and 2 in parallel

Thanks for pointing it out. I have made a simplification error. So the answer is 84/25 Ohms. Is it correct now? Can i consider 3 & 2 as the 1st pair of parallel resistors and 6 & 7 as the 2nd pair of parallel resistors. Thereafter should i add the 1st and 2nd pair in series? Btw its the...

After following what you said i got 25/84 Ohms as the answer for the 2nd circuit. Is it correct? But the 1st one is still confusing because of the connection in between

Homework Statement Calculate the total resistance of the 2 circuits given below Homework Equations R = R1+R2+R3... (1/R) = (1/R1) + (1/R2) + (1/R3) + ....The Attempt at a Solution I am unable to understand how to obtain the final resistance

What you explained is how to make the .15uH coil, right? What about the others? Is it possible to make them too?

I am looking forward to a small project. For this i need some inductor coils. I searched through the local shops, but i could find any inductor coil. According to what i know inductor coils are made by making loops using wires. http://www.instructables.com/id/Making-a-Simple-Induction-Coil/ Is...

Then how should i do part 2 with friction? Is it like this F=miu.R = 0.6 x (200N+300N) = 300N F=ma F-300 = (20N+30N)x1 F = 800N

so part 2 without friction from left to right F=ma F-30 = 20x1 F= 50N Then is it ok? And what about part 1 & 3 with friction?

This is how i did part 2 (without friction) F =ma =20x1 = 20N Then i did 2 parts with friction. part 1 The total mass of the system = 100Kg. g = 10Ms-2 Therefore mg = 1000N. Since mg = R R = 1000N F=miu.R =0.6X1000 = 600N Frictional force = 600N F=ma F-600 =...

If i have to redo the same question (all the parts) when the 3 boxes are on a rough surface of coefficient of static friction 0.6, how do i do it? Is it by using the equation F=miu.R? If so what should i substitute for F & R?

By using F=ma = 30x1 = 30N 20kg mass is touching it Then is 30N the the force exerted by 20kg on 30kg? I that the answer?

can you do the questions step by step. then i might be able to understand

for some reason i don't understand this :( :( Can someone try re explaining again in the simplest form and answer those questions as if you are doing the sum? (but in the simplest way) thanks for pointing it. corrected it