How to Calculate the Total Resistance in a Circuit?

  • Thread starter Thread starter [KNIGHT]
  • Start date Start date
  • Tags Tags
    Resistance
Click For Summary

Homework Help Overview

The discussion revolves around calculating the total resistance in two electrical circuits, focusing on the principles of series and parallel resistor combinations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss identifying pairs of resistors in series or parallel and simplifying the circuits step by step. Questions arise about specific connections and methods used to calculate total resistance.

Discussion Status

Participants have offered guidance on identifying resistor combinations and checking calculations. There is ongoing exploration of methods for both circuits, with some participants sharing their approaches and seeking validation of their results.

Contextual Notes

Some participants express confusion regarding the connections in the first circuit and the assumptions made about resistor configurations. There are references to specific resistance values in the circuit diagrams that are not provided in the discussion.

[KNIGHT]
Messages
18
Reaction score
0

Homework Statement


Calculate the total resistance of the 2 circuits given below
1-1.png


Homework Equations


R = R1+R2+R3...
(1/R) = (1/R1) + (1/R2) + (1/R3) + ....

The Attempt at a Solution


I am unable to understand how to obtain the final resistance
 
Physics news on Phys.org
General strategy: Look for pairs of resistors that are purely in parallel or in series. Then replace those pairs with their equivalent resistance. Then do it again, until you've simplified it enough.
 
After following what you said i got 25/84 Ohms as the answer for the 2nd circuit. Is it correct?

But the 1st one is still confusing because of the connection in between
 
[KNIGHT];4166877 said:

Homework Statement


Calculate the total resistance of the 2 circuits given below
1-1.png


Homework Equations


R = R1+R2+R3...
(1/R) = (1/R1) + (1/R2) + (1/R3) + ....

The Attempt at a Solution


I am unable to understand how to obtain the final resistance

Answer to Circuit # 2

Rt = R1 * R2 / R1 + R2

Give arbitrary values to each resistance, for example 100 Ohms each. Find a parallel pair and evaluate:Example 2 parallel resistor [Items 1 & 2] 100 Ohms each equals 50 Ohms, that is 100 Ohms divided by 2 resistors. Now add that value to the next resistor in series [ Item 4], you now have 150 Ohms. Find the series branch and add the resistance which equal 200 Ohms Item 7 & 5]. You now have 150 Ohms in parallel with 200 Ohms, evaluate them both in parallel and you arrived at a value of 85.714 Ohms for the entire circuit. Follow the same procedure for circuit # 1
 
Last edited:
[KNIGHT];4166918 said:
After following what you said i got 25/84 Ohms as the answer for the 2nd circuit. Is it correct?
It looks like you've forgotten to take a reciprocal somewhere. Check your work, or better yet, post it here so others can check.
But the 1st one is still confusing because of the connection in between
Can you identify any candidates for parallel or serial connections?
 
It looks like you've forgotten to take a reciprocal somewhere
Thanks for pointing it out. I have made a simplification error. So the answer is 84/25 Ohms. Is it correct now?

Can you identify any candidates for parallel or serial connections?
Can i consider 3 & 2 as the 1st pair of parallel resistors and 6 & 7 as the 2nd pair of parallel resistors.
Thereafter should i add the 1st and 2nd pair in series?

Btw its the resistance values that are marked in the diagram
 
Last edited:
[KNIGHT];4166957 said:
Thanks for pointing it out. I have made a simplification error. So the answer is 84/25 Ohms. Is it correct now?
Yes, the result is correct. I cannot comment on your methodology since you did not show it.
 
Here is the way i did it
considered 1 & 2 as a parallel pair and found their resistance and added it in series with 4. (group 1)
Then i added 7 & 5 in series and considered it as group 2.
The final answer was obtained by adding group 1 and 2 in parallel
 
[KNIGHT];4166980 said:
Here is the way i did it
considered 1 & 2 as a parallel pair and found their resistance and added it in series with 4. (group 1)
Then i added 7 & 5 in series and considered it as group 2.
The final answer was obtained by adding group 1 and 2 in parallel

Yes, that is a correct method.
 
  • #10
What about the method to solve the 1st first? Is it correct?
 
  • #11
[KNIGHT];4168142 said:
What about the method to solve the 1st first? Is it correct?

You'll have to be more explicit.

Any correct method should arrive at the same result...
 
  • #12
[KNIGHT];4168142 said:
What about the method to solve the 1st first? Is it correct?
Yes. Assuming that this was your method for the 1st circuit:
[KNIGHT];4166957 said:
Can i consider 3 & 2 as the 1st pair of parallel resistors and 6 & 7 as the 2nd pair of parallel resistors.
Thereafter should i add the 1st and 2nd pair in series?
That is a good approach.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
4
Views
2K
  • · Replies 23 ·
Replies
23
Views
3K
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 19 ·
Replies
19
Views
7K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K