Recent content by KungFu

The tensor is a mulitlinear function, but why?, I don't see the arguments. I have been told that it is linear in each variable, due to the distributivity of the field R (real numbers), but can I show it, or is it just by definition ?

yes, sorry, I had a typo in my description. it is an element of ##E\otimes E^*\otimes E^*## Can you please explain to me what the capital U and the w and v are in your expression? and also the X and the Y

I know that a tensor can be seen as a linear function. I know that the tensor product of three spaces can be seen as a multilinear map satisfying distributivity by addition and associativity in multiplication by a scalar.

Im very new to the terminologies of isometric basis and musical isomorphism, will appreciate a lot if someone could explain this for me in a simple way for a guy with limited experience in this field. The concrete problem I want to figure out is this: Given: Let ##v_1 = (1,0,0) , v_2 = (1,1,0)...

ok, but what about the potential energy? I can see that the expression m(a + g)v equals the derivative of the potential energy $$\frac{d(m(a + g)h)}{dt} = m(a+g)v$$ , the work done by a force lifting a mass a certain vertical distance is given by the change in potential energy , so from this...

ok, cool, that makes sense , thanks !

yes, that is correct , I wonder if you can get the answer in the book if you just view the problem in a different way? I am not sure how though. I fond this thread discussing the same problem, but the answers did not made it clear for me ...

Thanks for the detailed answer mate. So, to be sure I get this correct, when you work in the elevator frame, and using the conservation of energy in the same way as you did in the lab frame, you get: $$P_{contact} + P_{weight} + P_{chem} = \frac{dT}{dt}$$ $$P_{contact}=0 , P_{weight} = -...

I have found the apparent weight of the man in the accelerating elevator My question is about what speed I should use in the formula for the power output P = F ⋅ speed My common sense tells me that the speed I should us is the speed v the man is climbing the ladder , because if the...