Show that a (1,2)-tensor is a linear function

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Homework Help Overview

The discussion revolves around the properties of a (1,2)-tensor, specifically its characterization as a linear function or a multilinear function. Participants explore the definitions and implications of tensors in the context of linear algebra and multilinear maps.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants question the definition and representation of a (1,2)-tensor, particularly whether it belongs to specific tensor product spaces. There is an exploration of the nature of the tensor as a function and its linearity in relation to its arguments.

Discussion Status

The discussion is ongoing, with participants clarifying definitions and exploring the implications of the tensor's properties. Some guidance has been offered regarding the nature of tensors as multilinear functions, but there is still uncertainty about how to formally demonstrate this property.

Contextual Notes

There are references to potential typos and ambiguities in the initial descriptions, which may affect the understanding of the tensor's properties. Participants are also discussing the roles of vectors and covectors in the context of the tensor's definition.

KungFu
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Homework Statement
problem:
1a) show that a (1,2)-tensor T is a linear function T: ##E^* x E x E ##
(A (1,2)-tensor is a tensor that takes one vector from E and two covectors form the dual space #E^*#
Relevant Equations
I need some help on where to start.
I know that a tensor can be seen as a linear function.
I know that the tensor product of three spaces can be seen as a multilinear map satisfying distributivity by addition and associativity in multiplication by a scalar.
 
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Your explanation of ##(1,2)## is ambiguous. Is it an element of ##E\otimes E^*\otimes E^*## or an element of ##E^*\otimes E\otimes E##? Let us assume we have a tensor ##T\in E\otimes E^*\otimes E^*##. This means we have
$$
T=\sum_{\rho=1}^r U_\rho \otimes v_\rho \otimes w_\rho\; , \; (X,Y) \longmapsto \sum_{\rho=1}^r U_\rho \cdot v_\rho(X) \cdot w_\rho(Y) \in E
$$
What kind of function is ##T## then? The situation for ##T'\in E^*\otimes E \otimes E## is accordingly.
 
Last edited:
fresh_42 said:
Your explanation of ##(1,2)## is ambiguous. Is it an element of ##E\otimes E^*\otimes E^*## or an element of ##E^*\otimes E\otimes E##? Let us assume we have a tensor ##T\in E\otimes E^*\otimes E^*##. This means we have
$$
T=\sum_{\rho=1}^r U_\rho \otimes v_\rho \otimes w_\rho\; , \; (X,Y) \longmapsto \sum_{\rho=1}^r U_\rho \otimes v_\rho(X) \otimes w_\rho(Y) \in E
$$
What kind of function is ##T## then? The situation for ##T'\in E^*\otimes E \otimes E## is accordingly.

yes, sorry, I had a typo in my description. it is an element of ##E\otimes E^*\otimes E^*##

Can you please explain to me what the capital U and the w and v are in your expression? and also the X and the Y
 
KungFu said:
yes, sorry, I had a typo in my description. it is an element of ##E\otimes E^*\otimes E^*##

Can you please explain to me what the capital U and the w and v are in your expression? and also the X and the Y
The tensor isn't a linear function in that case. What is it?
 
fresh_42 said:
The tensor isn't a linear function in that case. What is it?

The tensor is a mulitlinear function, but why?, I don't see the arguments. I have been told that it is linear in each variable, due to the distributivity of the field R (real numbers), but can I show it, or is it just by definition ?
 
You can show it with the definition, see my corrected post #2. I made a copy and paste error and forgot to change ##\otimes## into ##\cdot## which I now did.
 

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