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Capacitors disconnected from the battery
I applied the equation... Q1 = C1*V1 = 23 µF * 9 V = 207 µC Q2 = C2*V2 = 10 µF * 9 V = 90 µC The results are incorrect. potential difference on each Capacitor is not 9V. Kind confusing... X(- laduch
- Post #3
- Forum: Introductory Physics Homework Help
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Capacitors disconnected from the battery
Capacitors C1 = 10 µF and C2 = 23 µF are each charged to 9 V, then disconnected from the battery without changing the charge on the capacitor plates. The two capacitors are then connected in parallel, with the positive plate of C1 connected to the negative plate of C2 and vice versa...- laduch
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- Battery Capacitors
- Replies: 3
- Forum: Introductory Physics Homework Help
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Net electric flux through torus
I had the same problem! you are right! thanks~- laduch
- Post #3
- Forum: Introductory Physics Homework Help