Capacitors C1 = 10 µF and C2 = 23 µF are each charged to 9 V, then disconnected from the battery without changing the charge on the capacitor plates. The two capacitors are then connected in parallel, with the positive plate of C1 connected to the negative plate of C2 and vice versa. Afterward, what are the charge on and the potential difference across each capacitor? The question ask for Q1, Q2(charge (µC)), and V1, V2(potential difference (V)). I used equation Q=CV which I think is the right equation to use... but there are some conceptual problems like what happens when "C1 connected to the negative plate of C2". When battery is disconnected from the circuit, how is the distribution of the voltage related to capacitors?