Recent content by lebprince

ok so i would use 0.05 x 27 = 1.35 and F = mxa so a = f/m = 27/2.5 = 10.8

ok..so i can find the torque on the body using r x Fnet, now is r the distance the center of the disk has moved? so 0.038 x 27 = 1.026? and F = mxa so a = f/m = 27/2.5 = 10.8

so i can use F = mxa?

umm am assuming i have to find the angular speed cause it would one one way to find V, but i know the Lrot = IW but i don't have Lrot

ok since we have 4 masses ; m1r^2 + m2r^2 + m3r^2 + m4r^2 so 0.2268

ok so the moment of inertia of the object is 1/2Mr^2 so = 1/2*2.5*(0.05)^2 = 0.003125

oh u meant deltat thanks

i still don't get how to solve the problem

Homework Statement A string is wrapped around a uniform disk of mass M = 2.5 kg and radius R = 0.05 m. (Recall that the moment of inertia of a uniform disk is (1/2)MR2.) Attached to the disk are four low-mass rods of radius b = 0.09 m, each with a small mass m = 0.7 kg at the end. The device...

Homework Statement At t = 15 s, a particle has angular momentum <5, 8, -3> kg · m2/s relative to location A. A constant torque <12, -13, 20> N · m relative to location A acts on the particle. At t = 15.2 s, what is the angular momentum of the particle relative to location A? The Attempt...

Ok there is a question after part c asking me for the final momentum of the gold nucleus long after the interaction with the alpha particle. i got the answer for that which was 2 * p1i, p1i is the initial momentum of the alpha particle. so 2 * 1.427e-19. now for part C i tried using the momentum...

Homework Statement An alpha particle (a helium nucleus, containing 2 protons and 2 neutrons) starts out with kinetic energy of 9.5 MeV (9.5106 eV), and heads in the +x direction straight toward a gold nucleus (containing 79 protons and 118 neutrons). The particles are initially far apart...

so if we have an inelastic collision what would i need to calculate DeltaEthermalA + DeltaEthermalB? Thanks

ok thanks i used Efsystem = Eisystem and figured it out. Thanks but when thermal energy gets involved it confuses me like this question suppose that in the collision some of the kinetic energy is converted into thermal energy of the two rocks, where Ethermal,1 + Ethermal,2 = 1.44106 J. What is...

Thanks i got that part right. can i get some help on this? Suppose the collision was elastic (that is, no change in kinetic energy and therefore no change in thermal or other internal energy of the rocks). In that case, after the collision, what is the kinetic energy of rock 2? i wanted...