Yes. Here it is:

$$\begin{aligned}

\nabla \cdot \mathbf E &= \frac \rho {\epsilon_0}\\

\nabla \cdot\mathbf B &= 0\\

\nabla \times \mathbf E &= -\frac{\partial \mathbf B}{\partial t}\\

\nabla \times \mathbf B &= \mu_0 \left( \mathbf J + \epsilon_0 \frac{\partial \mathbf E}{\partial t} \right)\end{aligned}$$

But I still can't see anything!

The light is in infrared, dummy.