Recent content by LiorSh

Of course - thank you very much for your help :)

Wow, thanks for the explanation. The answers are from my professor which he might be a little off. I wanted to make sure that my answers are correct before I tell him that he is wrong. He asked me to go over his solution and confirm if he is correct or not. The funny thing is that we have been...

Thanks for your help! it's from Berman, see original problem below: Also, for part d he got 13/49, and I get something completely different... What am I missing?

That's what I did... I'm getting (1/14) * (1+12 + 45) = 29/7. The answer though is 20/7. What did I forget?

So for that A(φ1+2φ2+3φ3) I'm getting (1*1)φ1+(3*2)φ2+(3*5)φ3= φ1+(6)φ2+(15)φ3 does that make sense?

Hi, thanks for the response and sorry for posting in in the wrong place. When I act with the operator on the functions, I get the eigenvalue correct? What happens to the constant of that function?

[Note from mentor: This thread was originally posted in a non-homework forum, so it lacks the homework template. Even though the solution was resolved there, the thread has been moved here for future reference.]So I'm given Φ = N(φ1+2*φ2 + 3*φ3) and the operator A with eigen values λ1 = 1, λ2...

Yes, that's what I thought. It makes sense now :) Thank you so much!

I'm not sure I completely understand. Is there some logic to which pairs I should pick? I mean, there is an infinite number of combinations.

So these are my results: for p = 1, and zero value = 2.4048, I for sure get the lowest energy, and the logic make sense. I took the lowest possible values of p and the zeros. then for the second lowest, p=2, and zero=2.4048, and for the thrid I got p=1, and zero = 5.5201. Doest it make sense?

a is 3nm, and L is 5nm. Also I thought that only the first column is for a symmtric cylinder, and the second colum is for a general soultion only. Isn't that the case? Thank you!

[Mentors' note: Moved from the technical forums, so no template] Hi, I have to find energy levels of an electron in a cylindrical shape. I know how to derive the formula below: However, I'm not sure which zero value and what intger p I need to use in order to find the lowest energy. If these...

There is much an easier way to do that- You need to assume that the big F = a(M+m1+m2) Now if you know that the "Ideal" situation that you are looking for - Masses m1 and m2 are stationary - write down the free-body diagram for each block IF you know that they are Not moving. once you figure...

It was a typo. In my notebook I used the right number. Thank you so much!

that means that we can use only 82655 of heat to melt the ice - which leaves us with 166500-82655= 83845 So it will melt 0.248 kg of the ice and the rest of the ice will remain in the bucket at 0 Celsius. Is that correct? or there is a different way to prove it?