Recent content by lolimcool

oops i did i did it again and got 1 0 5 0 1 -3 0 0 0 so dimension = 2?

Homework Statement find the dimension of the linear span of the given vectors v1 = ( 2, -3, 1) v2 = ( 5, -8, 3) v3 = (-5, 9, -4) Homework Equations The Attempt at a Solution so all i did was make it a matrix and put it in rref and i got [1 0 0] [0 1 0] [0 0 1] does this...

Homework Statement P is the point where the diagonals of the parallelogram abcd intersect one another let \alpha = AB and \beta = AD and let s and t be scalars such that AP = sAC and BP = tBD use vector algebra to show that s(\alpha + \beta) = AP = \alpha + t(\beta - \alpha)The Attempt at...

how do you guys type math and formulas and stuff on this forum?

wow i screwd up so x = -3 + 4t and y = 4 - 3t solved it and got -3x -4y + 7 = 0 which i believe is right thanks for your help :P

OH K, so that's what i initially did then i had x = -3 +t(3-1) => x = -3 +2t y = 4 + t(1-4) => y = 4 -3t then i got t= (x+3)/2 and t = (y - 4)/ -3 making both equations equal each other i get -3x -9 = 2y -8 -3x -2y -1 = 0 3x +2y + 1 = 0

oh i don't know then, i was just kinda following my notes(i obv copied them down wrong) how would i go about doing the first step then?

sorry i mean x = -3 +t(-1,3) y = 4 + t(1, -4) which gives me x = -3 + 2t and y = 4 + -3t i then isolate for t, make the equations equal to each other and i get 3x + 2y + 1 = 0

Homework Statement assume the existence of a fixed coordinatization of the plane in which 0 is the origin. Find an equation and give the coordinates of a third point that is on the line a:(-3,4) b:(1,1) Homework Equations The Attempt at a Solution ok so i get x = -3 + t(-1 3) y...

i didnt form a matrix, I am just wondering is it possible for a square matrix to have a column and be invertible

Can a square matrix with a column of all zero's be invertible?

cant z be either -1, 1, 3, -3 ?

yeah, i know I've tried to solve it, just keep getting stuck

x -2y + 4z = 7 0 (a^2 -1)y + az = 3 bz = -3

hey anyone want to help me start solving this matrix for a b c d where the system will be consistent [1 -2 4 | 7 ] [0 (a^2 - 1) a | 3 ] [0 0 b | -3]