Hi all, I recently saw a video on youtube where a fellow re-wires and old stator from a washing machine in order to reduce voltage from 400VAC to a safer value. See here.
Couple of questions:
1.) A before and after image/schematic is shown with a description of the configuration. Respectively...
I agree with you Dale regarding the water analogy - The whole picture usually is not stated as Jbriggs cleared up. With respect to the divided voltages considered as 'energy' I was looking at it from the point of potential energy being converted into kinetic. Water in a tank being released down...
I was going over some fundamentals with my son and I was trying to explain 'voltage drop' - To which appears to be some confusion on the net with respect to terminology. Many people are confusing 'voltage applied' and 'voltage dropped'.
First I will explain what I taught - Let us look at the...
This doesn't seem right..
In the video it states that to balance the gears you would apply a second equal weight to the blue gear.
The blue gear has 3x the rim force. Meaning for the gears to balance in this case, the red gear would need a weight of 3Kg, right? So again, your motor has to do...
Hmm ok..but let's say:
Load = 1Kg
R1=1cm
R2=2cm
R3=1cm
Aside from R3 now turning slower due to R1 & R2 sizing...would you still not only be generating 0.098 N.m at R3? Doesn't that in the end just boil down to a 1:1?
Scenario 2:
Load = 1Kg
R1=1cm
R2=2cm
R3=1.5cm
R3: 1KgF x 1.5cm = 1.5KgF.cm =...
and that's probably why I'm confused - All the YouTube videos 'introducing' the concept of gears display the configuration like this. So how ARE they coupled to achieve greater lifting strength?
It just didn't make sense to me how simply having a bigger gear next to the first one would amplify...
Apologies I should have included a diagram, please see below:
This is what I was referring to with the calculation: 1KgF x 1cm = 1KgF.cm = 0.098 N.m of torque
As for the motor, by "Max Load (holding)" I meant the max torque output is 0.098 N.m
As for the gear coupling, see below:
A motor...
Hi guys,
I was sizing up a servo motor the other day and started thinking. While we all know gear ratios will effectively "convert" speed into torque. I couldn't help wondering about the initial starting conditions.. The problem below...
Lets say I have a motor with a max load of 1Kg...
So just to confirm...in U235 the energy it takes to bind that neutron is also above the critical value resulting in fission. Where as in U238 binding energy is below the critical value therefore the neutron would need additional energy (kinetic) to hit that threshold of 7MeV?
"Critical energy is the excitation energy level of the nucleus above which fission can occur.
In fissile isotopes, like U-235, the critical energy is at or below the excitation of the nucleus when it has absorbed a neutron. So any absorbed neutron can cause fission in these nuclei, though they...
Thank you again!
I think I'm out of questions for now haha...I shall continue reading the documents provided so far.
You have all been great teachers, especially you Hiddencamper. Truly appreciate your time.
Thank you Jim for the link, I will definitely look into it! and Astronuc for the documents!
Quick question about this limit, with the reactor being at 12% I'm assuming it's still under pressure? Why would control rod withdrawals be disabled? and then scram at 15%? Also what exactly happens...
I was definitely visualizing that incorrectly, I imagined the re-circulation pumps simply sucking water out and then dumping it back in, like the loop in the diagram I uploaded..couldn't see the point of that.. so if I understood that correctly...by the time the feedwater reaches the core it...
You have helped immensely!
I have attached a diagram of the reactor setup...don't know exactly how accurate it is, but I have a few more questions in regards to this paragraph:
"So control rods are used to raise power up till around 45-50%. At this point, we start raising up the cooling water...
An excellent post, thank you HiddenCamper
I see what you mean by BWR's being easier to model...there's a lot of tail chasing in the PWR.
Earlier you stated that:
"[BWR] The turbine operates in pressure control mode. It will automatically modulate how much steam it draws from the core to...