Recent content by Mag|cK

What don't you like about the job?

i don't have any email besides the ones like hotmail/ yahoo, hence i can't register. Can you post my thread to the actuarial outupost and give me the link. Thx a lot.. :smile:

Hello. From the internet I have learned that memorization is the main thing in actuarial exams past the fourth exam. The more you advance, the more theoretical the actuarial studies become. Is it true? Does the mathematics slowly fade away the more you advance? For the memorization, is it like...

haha. i get it now. thx.

To make an orange dye, 3 parts of red dye are mixed with 2 parts of yellow dye. To make a green dye, 2 parts of blue dye are mixed with 1 part of yellow dye. If equal amounts of green and orange are mixed, what is the proportion of yellow dye in the new mixture? This is not a homework...

What's the difference between identity and equation? So it's not possible to integrate and come up with distance equation?

Well I have a set of equations, only based on that Fdrag= -0.5 c p a v^2. I just divide into horizontal and vertical component, mainly the force and acceleration. However to find the function of horizontal distance, I believe I have to integrate dVx/dt and then integrate it again. While...

I want to integrate dVx/dt = -(D v Vx) / m but v=sqrt(Vx^2+Vy^2) I have tried substitution method to eliminate Vy, but it's not possible (I have done this for hours). My question is, Is it even possible to come up with an equation of horizontal distance as a function of launch angle...

"Secondly, for calculations, for the vertical component, I need to divide the drag force calculation into 1.when the ball goes up and 2. when the ball goes down. Because in #1, gravity has negative value, and in #2, gravity has positive value in the equation. Right? Yet, why many sites i have...

And btw why is this thread moved? I really don't think this is introductory physics.

It's not that simple as horizontal velocity is changing due to air drag.

I think you are talking about projectile motion without air resistance? Nonetheless, in projectile with air resistance, is it possible to obtain an equation of maximum distance as a function of initial velocity and launch angle (as the variables only)?

yes i can. I have found the answer to my second post. Any answers on my first post?

I have another question: I have researched that for horizontal component (x), Fdrag= -0.5 C p A V Vx for vertical component (y), Fdrag= -0.5 C p A V Vy where V=square root(Vx^2+Vy^2) Isn't Fdrag for horizontal component is simply= -0.5 C p A Vx^2 and for vertical component, Fdrag = -0.5 C...

Hello. How do we derive: Maximum distance of a projectile as a function of initial velocity and launch angle. [taking into account the air resistance] Assuming mass of projectile, air viscosity, drag coefficient, etc are constants. Is there any sites giving the steps?