Drag force equation, projectile

AI Thread Summary
The discussion centers on the correct drag force equation for projectile motion, with two forms presented: F = C p a v^2 and F = 0.5 C p a v^2, with clarification needed on the value of C for a tennis ball. It is noted that the vertical component of drag force should be treated differently when the ball is ascending versus descending, as gravity's effect changes direction. The inquiry also questions why many resources simplify the vertical component into a single equation despite these differences. Additionally, there is confusion regarding the sign of angle X in the drag force equation when the ball is moving downward. The conversation seeks further clarification and resources on projectile motion with air resistance.
Mag|cK
Messages
36
Reaction score
0
Hello everyone. I have researched from the internet that the drag force equation for projectile motion is either F= C p a v^2 or F= 0.5 C p a v^2. Which one is the correct one? The initial speed I am dealing with is about 20m/s. And what's the value for C for a normal tennis ball. Other sites give too big of a range value for C.

Secondly, for calculations, for the vertical component, I need to divide the drag force calculation into 1.when the ball goes up and 2. when the ball goes down. Because in #1, gravity has negative value, and in #2, gravity has positive value. Right? Yet, why many sites i have seen including the posted PDF files on the internet about projectile motion calculation with air resistance just simply generalize the vertical component calculation into 1 equation?

Lastly, about the equation
a(acceleration vertical component)= -1/m (Fdrag sinX + mg)

when the ball travels downward, isn't angle X negative, hence giving the value sinX negative, and consequently positive drag force?

And do you have any suggestions for good 'projectile with air resistance' sites?

Thank you very much.
 
Physics news on Phys.org
Gravity would always be a downwards (negative vertical) force. The only force that varies is drag. The difference between the .5 x Cd and the 1.0 x C equations is C has incorporated the .5, while Cd is the coefficient of drag. Cd for a tennis ball will vary based on the fuzz and the spin.
 
"Secondly, for calculations, for the vertical component, I need to divide the drag force calculation into 1.when the ball goes up and 2. when the ball goes down. Because in #1, gravity has negative value, and in #2, gravity has positive value in the equation. Right? Yet, why many sites i have seen including the posted PDF files on the internet about projectile motion calculation with air resistance just simply generalize the vertical component calculation into 1 equation?"

Anyone has any answers on this one?
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top