Recent content by manan1

tried it, doesn't work. the new virtual work equation becomes... -M/a - F - qa/4 = 2N => N = -11.7

The basic idea that you need to understand is W = \int^{1}_{2} P dv P*V = n*R*T Here n is the number of moles of the gas, R is the Boltzmann gas constant and T is the temperature. For an isothermal gas of fixed mass, n, R, and T are all constants. Therefore P = (n*R*T) / V...

i induce the same amount of rotation in both, and than follow to measure the change in the distances

PROBLEM 1 Homework Statement The frame in the figure is supported by a hinge in A and a roller in G. It is loaded by a couple = 14 kN*m in B, a force = 12 kN in D and a distributed force = 4 kN/m on section EG. = 1.4 m. Calculate the normal force in C. Use the correct signs...

Ok, forget my first post and the question therein. I got how the problem works. However I still would like an answer to the question I posed in my second post, it would clarify my understanding of these things. I used some other trigonometric ratios. Thanks

Also I do not understand how one could possibly arrive at the above trigonometric relations. Maybe if I saw the diagram it would be clear, but to the extent of my understanding of your words, it does not make sense . I guess without the diagram I won't understand anything properly.

I believe I am in the same course and am having difficulties with this problem. The imagecave server is down so i can't have a look at your diagram. If you would reupload the image if you have it I would be very grateful. I want to ask certain questions that arose in my head from this...