Isothermic compression question. Need help

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SUMMARY

The discussion centers on calculating heat energy transfer during isothermal compression of a gas, specifically 0.253 m³ compressed from 1 bar to a volume of 0.0313 m³. The key equation used is Q = nRT ln(V₂/V₁), where n is the number of moles, R is the Boltzmann gas constant, and T is the temperature. The user seeks clarification on determining T, which can be derived from the ideal gas law, PV = nRT. The final calculation yields Q = 0.192, confirming the relationship between work done and heat transfer in isothermal processes.

PREREQUISITES
  • Understanding of ideal gas laws, specifically PV = nRT.
  • Familiarity with isothermal processes in thermodynamics.
  • Knowledge of logarithmic functions and their application in physics.
  • Basic calculus for evaluating integrals in thermodynamic equations.
NEXT STEPS
  • Study the derivation of the ideal gas law and its applications in thermodynamics.
  • Learn about isothermal processes and their characteristics in gas behavior.
  • Explore the concept of work done in thermodynamic systems, particularly in isothermal conditions.
  • Investigate the relationship between pressure, volume, and temperature in real gases versus ideal gases.
USEFUL FOR

This discussion is beneficial for students studying thermodynamics, particularly those focusing on gas laws and isothermal processes. It is also useful for educators and professionals seeking to reinforce their understanding of heat transfer in gas compression scenarios.

rigger100472
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Homework Statement


The question I am stuck on is "0.253 m of gas is compressed isothermally from a pressure of 1 bar until its volume is 0.0313 m. Calculate the heat energy transfer. "

Homework Equations


I understand that work done = Heat transfer because it is isothermal but the equation I have to work with is:

Q=nRT ln V^2/V^1

I don't want the answer to this because I would like to understand, I just don't know what nRT is and how on Earth do I find T if it is not given in the answer.


The Attempt at a Solution


I have not attempted to answer yet
 
Last edited:
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rigger100472 said:
The question i am stuck on is "0.253m^3 of gas is co

What is your question?
What are your relevant equations?
Let's see your attempt at solution.
 
Sorry about the post being incomplete (don't know what happened). I have now edited the original post.
 
Hmm this question is bothering me. I definitely used to know how to do it.

I know that in an isothermal compression nRT = P1V1 = P2V2 = constant. Maybe that's how you find T, since you know P1V1 is.

EDIT: I think it is possible that this answer is correct because you're not subbing in a variable PV for NRT, you are subbing in P1V1, which are known, and known to be constant.
 
The basic idea that you need to understand is

W = \int^{1}_{2} P dv


P*V = n*R*T

Here n is the number of moles of the gas, R is the Boltzmann gas constant and T is the temperature. For an isothermal gas of fixed mass, n, R, and T are all constants. Therefore

P = (n*R*T) / V


\int^{1}_{2} P dv
= \int^{1}_{2} (n*R*T) / V dv
= (n*R*T)*\int^{1}_{2} 1 / V dv
= (n*R*T) * ln (v_{2}/v_{1})

Although I am not sure how you can find T, you can surely find n*T as you know the volume pressure and R you can use the equation PV = nRT to get n*T. That value you can use in your equation to find your answer

And the relationship PV = nRT comes from the ideal gas relationships which state that

\frac{P_1*V_1}{T_1} = \frac{P_2*V_2}{T_2}

As this relationship is true we can say for every mole of gas

\frac{P_1*V_1}{T_1} = \frac{P_2*V_2}{T_2} = K

This constant K is the Boltzmann gas constant R, and n is the number of moles of the gas.
 
Ok thanks for the info guys, I had a go at the question and this is what I came up with. What do you think?

Q=W=nRT∫_(V_2)^(V_1)▒PdV
but nRT=PV
Q=PV∫_(V_2)^(V_1)▒PdV
During isothermal compression
P_1 V_1=P_2 V_2⇒PV is a constant

In this case

PV=0.253

⇒P=PV/V=0.253/V⇒P_2=0.253/V_2 =7.167Bar


⇒Q=PV∫_(V_2)^(V_1)▒〖0.253/V dV〗

⇒Q=PV[0.253lnV]_0.0313^0.253
⇒Q=0.253(0.253ln0.253-0.253ln0.0313)

⇒Q=0.253(0.253ln0.253-0.253ln0.0313)
⇒Q=0.192
 

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