Statics 2D Virtual Work problem regarding calculation of Normal force

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Discussion Overview

The discussion revolves around solving a statics problem involving the calculation of normal force using the principle of virtual work. Participants explore the application of virtual work in two specific problems, addressing discrepancies between results obtained through virtual work and equilibrium equations.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents a problem involving a frame supported by a hinge and roller, loaded by various forces, and seeks to calculate the normal force using virtual work, noting a discrepancy with the equilibrium method.
  • Another participant questions the assumption that the angular displacements δθ1 and δθ2 are equal, prompting a discussion on the validity of this assumption.
  • Some participants propose alternative approaches, such as assuming equal virtual displacements δu1 and δu2 to derive the rotation, but report that this method does not yield the expected results either.
  • A later reply presents a modified virtual work equation leading to a different value for the normal force, indicating ongoing exploration of the problem.

Areas of Agreement / Disagreement

Participants express differing views on the assumptions made regarding virtual displacements and rotations, with no consensus on the correct approach or solution to the problems presented.

Contextual Notes

Participants note that their calculations depend on specific assumptions about displacements and rotations, which may not hold true in all cases. The discussion reflects uncertainty regarding the application of the virtual work principle in these scenarios.

manan1
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PROBLEM 1


Homework Statement



VIRT_LR_009.jpg


The frame in the figure is supported by a hinge in A and a roller in G. It is loaded by a couple = 14 kN*m in B, a force = 12 kN in D and a distributed force = 4 kN/m on section EG. = 1.4 m.
Calculate the normal force in C. Use the correct signs for tension and compression. Hint: Solve using the principle of virtual work and use previously mastered methods to check your answer.


This is a problem from mastering engineering, the statics book. I can solve the problem using equilibrium equations, but i want to know what i am doing wrong with when I am doing using the virtual work theorem.

Homework Equations



\deltaW = 0
\delta\theta small → tan ( \delta\theta) ≈ \delta\theta ;


The Attempt at a Solution



DSC00011.jpg



\delta\theta_{1} = \delta\theta_{2} = \delta\theta


\delta\theta_{1} = \delta u_{1}/a
\delta\theta_{2} = \delta u_{2}/2a


LET
\delta u_{2} = \delta u

\delta u_{2}/2a = \delta u_{1}/a → \delta u_{1} = \delta u/2
\delta u_{3}/(a/2) = \delta u/2a → \delta u_{3} = \delta u/4
\delta u_{5} = \delta u_{1} = \delta u/2
\delta u_{4} = \delta u_{2} = \delta u

\delta W = 0

Therefore
-M*\delta\theta-N*\delta u_{5}-N*\delta u_{4}-F*\delta u_{2}-qa*\delta u_{3} = 0
\delta u ≠ 0
-M*\delta u/2a-N*\delta u/2-N*\delta u-F*\delta u-qa*\delta u/4 = 0
-\frac{3}{2}N = M/2a + F + qa/4
N = -12.2666... kN


But the answer should be -17.6 kN according to equilibrium equations.



PROBLEM 2

Homework Statement



attachment.php?attachmentid=40380&stc=1&d=1319724126.jpg


The frame in the figure is supported by a hinge in A and a roller in G. It is loaded by a couple = 4 kN*m in D, a force = 6 kN in B and a distributed force = 1 kN/m on section EG. = 1.5 m
Calculate the shear force in C with the sign convention as shown in the figure. Hint: Solve using the principle of virtual work and use previously mastered methods to check your answer.

Homework Equations



\deltaW = 0
\delta\theta small → tan ( \delta\theta) ≈ \delta\theta ;


The Attempt at a Solution



attachment.php?attachmentid=40381&stc=1&d=1319724126.jpg


I have no idea how to calculate the virtual displacement for the force F at B.
 

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Last edited:
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For problem 1, why are you sure that δθ1=δθ2 ?
 
i induce the same amount of rotation in both, and than follow to measure the change in the distances
 
I would try the other way around : assuming a deplacement δu2=δu1 and then calculate the rotation
 
tried it, doesn't work.

the new virtual work equation becomes...

-M/a - F - qa/4 = 2N
=> N = -11.7
 
Last edited:

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