Recent content by maplesyrup23
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Limit of a function at a point (picture included)
I'm trying to find the limit of this function at 0. I know that for the abs (x) graph, 0 is not differentiable because of abs (h)/h, but I'm not certain about the point on this function. There is no function given, only the picture. Thanks in advance!- maplesyrup23
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- Function Limit Point
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Log Question - Relationship between two points on log function
yeah Tyler was right. You're supposed to be using the given log values in the OP to do this question. log 3 = 0.477, and log 2 = 0.301- maplesyrup23
- Post #8
- Forum: Precalculus Mathematics Homework Help
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Log Question - Relationship between two points on log function
Crap, thanks anyways.- maplesyrup23
- Post #5
- Forum: Precalculus Mathematics Homework Help
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Log Question - Relationship between two points on log function
It is possible I am reading it wrong, I haven't seen it written like this before, look at the printscreen. EDIT: Sorry about the size of the image.- maplesyrup23
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Log Question - Relationship between two points on log function
Hi Physics Forums, I understand that I usually need to show that I've attempted a question in order to get feedback, but I have absolutely no idea how to approach this one Calculus Log question. Base = 10 log (2) = 0.301103, log (3) = 0.47715 a.) Find log base 6 (5) b.) Estimate...- maplesyrup23
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- Function Log Points Relationship
- Replies: 11
- Forum: Precalculus Mathematics Homework Help
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How Far Ahead is the Car from the Truck After Passing?
Alrighty then, thanks much- maplesyrup23
- Post #9
- Forum: Introductory Physics Homework Help
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How Far Ahead is the Car from the Truck After Passing?
Right, right, thanks. So now, how do I find the distance between the car and the truck 10s later? Could you give me the steps? I suspect that I should add the 4s distance and the truck distance... Or is the answer just the 4s distance of the car?- maplesyrup23
- Post #7
- Forum: Introductory Physics Homework Help
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How Far Ahead is the Car from the Truck After Passing?
okay then, d(truck)= 18m/s x 10s = 180m d(car) = vit + 1/2 at^2 Using 4s, d = 96m Using 10s, d =300m Where do I go from here to get my final answer?- maplesyrup23
- Post #5
- Forum: Introductory Physics Homework Help
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How Far Ahead is the Car from the Truck After Passing?
Using which time?- maplesyrup23
- Post #3
- Forum: Introductory Physics Homework Help
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How Far Ahead is the Car from the Truck After Passing?
Homework Statement A car traveling @ 20 m/s pulls out to pass a truck traveling @ 18m/s. The car accelerates for 2.0m/s^2 for 4s and maintains new velocity. (c.) If the car was originally 8.0 m behind the truck when it pulled out to pass, how far in front of the truck is the car 10.0 s later...- maplesyrup23
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- Kinematics Kinematics problem Physics
- Replies: 8
- Forum: Introductory Physics Homework Help