Recent content by Marshillboy

  1. M

    Why does enthalpy change depend only on temperature for ideal gases?

    This isn't a formal homework question so much as a conceptual question for my own edification. I'm reading my textbook's section on enthalpy and energy, and given the expression: ΔH=nCpΔT It states that, "we can use this expression to represent the change in enthalpy when n moles of an...
  2. M

    Is EE the Right Choice for a Computer Science Major with a Dislike for Physics?

    Like 85% of people who applied to the University of Washington's Computer Science program, I was rejected and am now going into my Junior year without a major. Last quarter, I took the first introductory EE class and found it pretty enjoyable. As much as I like the idea of going with EE as a...
  3. M

    Engineering Set time delay for a comparator Op-amp circuit

    I got it. After many solid hours debugging, turns out one of the supply rails was floating. Oops. Thanks for the help!
  4. M

    Engineering Set time delay for a comparator Op-amp circuit

    Homework Statement [See attached diagram] I'm trying to design a circuit that connects to the input terminals of the noninverting input of this comparator circuit such that: -The input to my circuit consists of a SPST switch and a 9 volt battery -When the switch is thrown on, there would be a...
  5. M

    Graduate Taking the inverse laplace of this?

    I see. So, doing so would give me \frac{-s}{(s+1/8)^{2}+63/64}+\frac{-1/4}{(s+1/8)^{2}+63/64} The second fraction would be simple to use with the e^{at} sin(bt) identity since it's just a coeffecient on top, but what about the first?
  6. M

    Graduate Taking the inverse laplace of this?

    How do I take the inverse laplace transform of something that looks like this? It's part of a larger piecewise-defined second order differential equation, but this is the part I'm stuck on. (-4s-1)/(4s^2 + s + 4) Completing the square doesn't work for the bottom, so I figure I need to...
  7. M

    Calculating variable gain for difference amplifier

    Homework Statement http://img706.imageshack.us/img706/263/hwstatement.png Homework Equations KCL/Node voltage method Ideal op-amp rules The Attempt at a Solution I solved a previous, similar problem where the gain was fixed and the resistor mass going into the inverting and noninverting...
  8. M

    Thevenin Equivalent with dependent sources

    Oh I see, that's pretty clever. You're basically creating a linear equation for the potential across the desired terminals and analyzing its slope and intercept for determining the Thevenin equivalent voltage and resistance. Interesting.
  9. M

    Thevenin Equivalent with dependent sources

    Ouch, you're right. That's what I get for being lazy. I did happen to get the correct value for the Thevenin voltage at least. I understand how you got the Thevenin voltage when I=0, but how did the expression give the Thevenin resistance?
  10. M

    Thevenin Equivalent with dependent sources

    Thanks for the reply! So, I solved the circuit you provided using the node voltage method and substituted in the equivalent equations for Vx and Ix (Vx = 6-a, g' = 6, Ix = b-a/1k, etc). However, when I got to the point that I needed to solve my equations, the I from the imaginary source was a...
  11. M

    Thevenin Equivalent with dependent sources

    Homework Statement See attached image Homework Equations Thevenin's theorem Node voltage method? The Attempt at a Solution So if I want the current Io, I believe I need to treat the 1K resistor as an open circuit in finding the Thevenin equivalent. I think setting ground to be the bottom...
  12. M

    Engineering Thevenin equivalent of an LED circuit

    Homework Statement How would I go about determining the Thevenin equivalent of a simple circuit involving a battery and an LED? I suppose there could be a series resistor to prevent excess draw and burning out of the diode. This question seems very odd since LEDs by definition don't...
  13. M

    Voltage drop direction across resistors and ideal current sources

    That's pretty fantastic, thanks so much for your help.
  14. M

    Voltage drop direction across resistors and ideal current sources

    Oh! So what you're saying is that we know it will always be 3A through that branch, according to the ideal source. However, the power supplied is a matter of how much of the 3A of current is actually supplied by this source. If all of the 3A is externally supplied, the potential across the...
  15. M

    Voltage drop direction across resistors and ideal current sources

    Thanks! That's pretty helpful. So, for the first answer you're saying that since I arbitrarily chose a reference node, the -2V potential only means the relative difference between the potentials of the two nodes and not necessarily it's actual value? One more question regarding potential...