Recent content by MasterVivi

Okay, think I got it You're right it should be +5I3 because it's with the current, just like I2 works out in the first loop equation L1=2-4I1+4I2=0 Using this to solve for I1 I1=I2+(1/2) Now I did this wrong, so going back through the derivation of this loop equation...

Using the one know current, the current would be the same at a correct? If so you couls just do Va-Vb=-24V+(I)(10) =>-24+(0.0706)(10)=-23.294 Which implies Vb-Va=+23.294V Or is this still the wrong path? Do I need to use loop rules and find the unknown values of the current when it...

Okay, re-attempted using loop one and loop two, does, this seem more accurate? L1=12V-I1(2)+I2(1)-10V+I2(3)-I1(1)=0 => L1=2V-4I1+4I2=0 L2=-3(I2)+10V-I2(1)-I3(1)-8V-I3(2)=0 => L2=2V-4I2-5I3=0 => L2=2-4I2-5(I1-I2)=0 => L2=2-4I2-5I1+5I2=0 => L2=2-5I1+I2=0 So from there...

This is useful, in a case like mine you wouldn't want multiple I notations of current cause then your introducing variables you don't know right? should I go opposite the current from b→a? like ΔV=-(0.0706A)(10Ω)+12V=12.706V Since that is the only value of I given?

Homework Statement Find the potential difference between points a and b. Picture of Circuit involved. Homework Equations V=IR ΔV=Vb-Va The Attempt at a Solution Pretty much completely lost, due to the only one current shown I'm not sure which way the current flows through...

Homework Statement Apply the loop rule to two of the three loops to calculate I1,I2,and I3. Picture of DC circuit involved Homework Equations V=IR The Attempt at a Solution L1=2v+2I2-4I1=0 (simplified) and L3=4-4I1-5I3=0 But if you work through the algebra you'd get I2=1...

Just dawned on me what you were saying R2-2.125R+0.1444=0 is simple haha Thank you so much.

Am I just being an idiot? is the -4r2 supposed to be under the root? I mean that makes sense to me in terms of a quadratic formula -4AC being under the root.

I've tried this it kinda looks like R=1/2[(2.885)-0.76]±√((2.885-0.76)^2)-0.5776 What messes with me is that the root term should just cancel most itself and become the first number again. My professor just got back to me saying that his answer for the root term was 0.9895. which if this...

Homework Statement A resistor with resistance R is connected to a battery that has emf 15.0[V] and internal resistance r = 0.38[Ω]. For what two values of R will the power dissipated in the resistor be 78.0 W? Homework Equations P=I2R=(ε2/(R+r)2)R The Attempt at a Solution...