Recent content by mattwkeller
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Electromagnet Polarity Switching for Reversed Motion
Understood. The difference in that case is the rotor has copper inlays or aluminum bars arranged on the steel shaft. In this case would the reversible solenoid need those in order to reverse? Would it still reverse but not be as efficient with a plain steel plunger?- mattwkeller
- Post #7
- Forum: Electrical Engineering
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Electromagnet Polarity Switching for Reversed Motion
So could a three phase solenoid with a coil for each phase be bidirectional for a ferrous non-magnetic plunger?- mattwkeller
- Post #5
- Forum: Electrical Engineering
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Electromagnet Polarity Switching for Reversed Motion
I am referring to non mechanical linear motors, similar to coil guns or induction rails on roller coasters. I thought I understood the concept in solenoids until I found out about induction linear motors without permanent magnets, which seem to counter the operation of a one-way solenoid.- mattwkeller
- Post #4
- Forum: Electrical Engineering
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Electromagnet Polarity Switching for Reversed Motion
I am trying to understand the differences in design between a traditional solenoid with a ferrous plunger vs linear motors that use either induction or permanent magnets. From my understanding, a traditional solenoid, whether DC or AC, cannot fire in both directions with polarity switching since...- mattwkeller
- Thread
- Electric motor Electromagetism Electromagnet Motion Polarity Solenoid
- Replies: 7
- Forum: Electrical Engineering
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Is There an Error in My Kirchoff's Loop Problem Solution?
Okay, thank you.- mattwkeller
- Post #7
- Forum: Introductory Physics Homework Help
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Is There an Error in My Kirchoff's Loop Problem Solution?
Yes, sorry about that. They are in amps. I missed the scientific notation in my matrix. Should I1= -8.461e(-4)?- mattwkeller
- Post #5
- Forum: Introductory Physics Homework Help
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Is There an Error in My Kirchoff's Loop Problem Solution?
Sorry, struggling getting the picture up...in the meantime my answers are: I1=-8.461 I2=-.00392 I3=-.00477- mattwkeller
- Post #2
- Forum: Introductory Physics Homework Help
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Is There an Error in My Kirchoff's Loop Problem Solution?
Homework Statement Find the currents going through each resistor. Homework Equations V=IR The Attempt at a Solution [/B] I have the problem worked out and I can't find any errors in my work. The issue is that my professor has: I1=-.0843 I2=.086 I3=.0017 However my physics professor is...- mattwkeller
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- Circuit analysis Kirchoff's loop Loop
- Replies: 6
- Forum: Introductory Physics Homework Help
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What units are BTU compatible with?
Homework Statement Im given a problem where I am supposed to utilize the concept of conservation of energy to find an object initial velocity. There is a force that works on an object. They give me the amount of work done in BTU and the other units are in lb, ft/sec, ft/sec^2...Then I...- mattwkeller
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- Btu Units
- Replies: 2
- Forum: Introductory Physics Homework Help
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Why doesn't the inside of a conducting cup transfer charge?
Ahh that makes sense. Thank you!- mattwkeller
- Post #13
- Forum: Introductory Physics Homework Help
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Why doesn't the inside of a conducting cup transfer charge?
So even when a conducting object is placed on the inside surface of the cup, it isn't enough to disrupt this electron formation? Just seems hard to believe that none of the charge transfers!- mattwkeller
- Post #11
- Forum: Introductory Physics Homework Help
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Why doesn't the inside of a conducting cup transfer charge?
Oh, the electrons would end up forming a pattern the maximizes distance, but since they are repelling the would only end up on the outside of the cup. Correct?- mattwkeller
- Post #9
- Forum: Introductory Physics Homework Help
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Why doesn't the inside of a conducting cup transfer charge?
The charges would distribute equally throughout the metal, trying to get as far away from each other as possible...it would be a pattern that maximizes distance in between each charge.- mattwkeller
- Post #7
- Forum: Introductory Physics Homework Help
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Why doesn't the inside of a conducting cup transfer charge?
So F=kqQ/r^2 and E=kQ/r^2As the distance gets smaller the force and field strength increases. Is this what I'm supposed to be relating?- mattwkeller
- Post #5
- Forum: Introductory Physics Homework Help