Recent content by mcastillo356

Is there anything equivalent to CERN around you? Fermilab, in the USA, for example?I might be talking nonsense. 😒 Just for another trip.

Yes, I think so.

https://theory.cern/visitor-info As I see, there are several restrictions and conditions.

Thank you very much @anuttarasammyak, you've solved every doubt.

PICTURE ##(a)## The waves in front of the source are compressed, so we use the minus sign in ##\lambda=(v\pm{u_s})/f_s##. ##(b)## We calculate the received frequency using ##f_r=[(v\pm{u_r})/(v\pm{u_s})]f_s##. ##(c)## For a moving receiver, we use the same equations as in Parts ##(a)## and...

¿Maybe Jurassic Park? The novel and the movie mentions fractals and chaos theory.

At first glance, ##m\vec{g}=\vec{F_n}## But I don't know how to solve it if I must consider geometry. ##V=\cfrac{1}{3}\pi\,r^2\,h## Neither how to deal with ##\alpha## at the bottom: ##A=\cfrac{1}{2}\text{base}\times{\text{height}}##, suposing an isosceles triangle. Interesting. What kind of...

How does my arithmetic end up with ##1089##?. I don't understand. Maybe missing something of the statement?. Attempt The statement imposes to arrange the digits so they must be always three.

If I have understood, your example ends up with ##999## Counterexample 1- ##495## 2- ##594## 3- ##594-495=99## 4- ##99## 5- ##99+99=198## ##999\neq{198}##

Last step is this way $$mc^2t^{-1/2}\bigg |_{1}^{1-\frac{u_f^2}{c^2}}=mc^2\left (\frac{1}{\sqrt{1-u_f^2/c^2}}-1\right )$$

$$\displaystyle\int_0^{u_f}m\Bigg (1-\cfrac{u^2}{c^2}\Bigg )^{-3/2}\,u\,du=m\displaystyle\int_0^{u_f}\Bigg (1-\cfrac{u^2}{c^2}\Bigg )^{-3/2}\,u\,du$$ $$1-\cfrac{u^2}{c^2}=t\Rightarrow{-\cfrac{2u}{c^2}}\,du=dt\Rightarrow{u\,du=-\cfrac{c^2}{2}\,dt}$$ $$m\Big (-\frac{c^2}{2}\Big...

As in classic mechanics, we will define kinetic energy as the work done by the net force in accelerating a particle from rest to some final velocity ##u_f##. Considering one dimension only, we have...

Understood inmediatly. Thanks Forum.

Let me think it over again. Your reasoning is perfect. I must be wrong somewhere, but still the change of variable in ##R-10## keeps me wondering.

Why in the change of variable from ##p## to ##v## vanishes ##m##. And which is the behavior of ##c##: is this last an invariant of the derivative?. These are my doubts.