Homework Statement
I'm struggling with this, I have series of data for the deflection of a cantilever beam and the corresponding output voltages from a strain gauge, wheatstone bridge and amplifier circuit.
I'm trying to find the relation between voltage output and force, i.e. Force = K x...
Homework Statement
Pendulum of unknown length, l, has period of 9.32 seconds. Length is increased by 1 metre, and time period increases to 9.734 seconds. Calculate original length of pendulum and determine whether the experiment was conducted on earth. Hint: g is not assumed to be 9.81 ms^-2...
Homework Statement
If in an open water channel, the approach speed of an incompressible ideal fluid, of constant depth h1, is not too large, a small bump in height H (H<< h1) in the base of the channel will cause a dip Δh (Δh << H) in the water level directly above it, such that h1 = Δh + H...
Hi thanks for the reply
If I make V1 the subject, I get P2V2T1 /P1T2, right so far? :S
But I don't see how to substitute it into the first equation?
P1 * (P2V2T1 /P1T2) = P2V2^2
Homework Statement
Calculate a value of R, specific gas constant for air, from the values you have.
Also calculate the work done in the compression process.Homework Equations
Pv = RT
ρair = 1.2 kg/m^3The Attempt at a Solution
Have P,V and T data from an adiabatic compression. I think I need...
Thanks for the reply,
So I multiply both sides of P2/P1=15 by P1 to get P2,
101325 * 15 = P2 = 1519875 Pa
Not sure how to form the equation involving only P & T...
Something like T2/T1 = (P2/P1)^((n-1)/n)
EDIT:
so (P2/P1)^((n-1)/n) = 15^(1.1 - 1)/1.1 = 1.2791
1.2791 = T2/T1
T1*1.2791 =...
Homework Statement
Using a value of n of 1.1, calculate the final pressure and temperature when the cylinder is compressed rapidly with a compression ratio of 15.
Starting pressure = 101.325 kPa
Starting temp = 298 K
Homework Equations
(V2/V1) = 15
The Attempt at a Solution...
I have just seen it now, I was expanding the brackets out before, but if I don't do that, on the 2nd equation where we have
5(x-2.5) for x=2.5, this is 5(2.5-2.5) = 0...must've made an error when expanding them out. thanks!
Thanks, well at least I have the right answer.
I think I'm doing something wrong with the bending moment equations in that case because I get something different for each one:
for 1 < x < 2.5
M = 12.98x - 0.0951x^2 - 10(x-1)
x = 2.5, M = 16.86 kN*m
for 2.5 < x < 4
M = 12.98x -...
many thanks for pointing those out!
With regard to the moment being different depending on which equation I used, what about when I use the one for 2.5< x <4, shouldn't this give the same value as the equation for 1 < x<2.5 provided I used x = 2.5 ?
I've redone it and come up with this...
but aren't there two depending on which side of 2.5 x is? ie. 31.855625 kNm and 18.855625 kNm
EDIT:
I have done tau_max = Mc / I for both:
(31.85 x 10^3 N x 0.125 m)/ 2.1484 x 10^-4 m = 18.53 MPa
(18.856 x 10^3 N x 0.125 m) / 2.1484 x 10^-4m = 10.97 Mpa
So the beam cannot support these...