sorry so if i did it like this
since i have 500 and sin 35 using that i can get the perpindicular force which is also the hypoteneuse . so sin35 = 500/z . z = 871.7 then plugging that into your equation
we get 871times 1.5 times sin35 = .25sin35 F
solving for F we get 5230.3
dividing...
hey drizzle,
so using your formula,
Fmax[1.5]sin35o=F[0.25]sin35o
we wud end up with 500 which is the force applied by the man
500[1.5]sin35o/.25[sin35]= 3000 N
3000N / 9.81 = 305.8 kg's
i hope that's right
What is the maximum mass of rocks one can lift using a wheelbarrow PLEASE HELP!
Homework Statement
A man is using a wheelbarrow to transport rocks across the garden. The man can generate a maximal vertical force of 500N to lift the wheelbarrow. If the centre of mass of the rocks is .25m...