Recent content by michelp

so if I'm getting it right, it depends on the initial condition, right? if the cylinder at first only does translation, then the friction would be against the speed of center of mass, right?

I'm sorry, could you expand more on that?

TL;DR: I may have some problems with sign of convention and stuff Attempt at solution and correct answer is attached. the linear acceleration indicates that the friction actually is in the same direction as linear speed. Why is the angular acceleration anticlockwise here, against the...

Turns out the problem really was the sign of convention being inconsistent. I hope I got it right this time. I'm still a little confused with the LaTeX so I'll be using my handwriting for now.

This makes so much more sense, thank you so much. But if I had used the pulley as frame of reference and applied pseudo forces would ## T – m_1 g = m_1 a## and ##m_2 g – T = m_2 a## still be usable?

Thank you so much!

Sorry to reply twice, but I did the early steps with my teacherand thats what he wrote. I assume that's incorrect?

Ahhh im so sorry for my handwriting T_T

I'm a high school student and my teacher signed me up for some kind of olympiad and now I'm learning stuff, but at a pretty slow pace. I study using Halliday's book and sometimes also Morin, but I still think his problems are a little difficult. Anyhow, I'm grateful to have found this website...

I hope the sketch is good enough My attempt: anything with k means it's the pulley's. ak means the pulley's acceleration, xk means the pulley's rope length. So my idea here was to use the constraint a1 = 2ak - a2, find the eq for ak and a2 in terms of a1, group them and find a1, but instead I...

Is it possible to do if we use m2 as frame of reference?