Recent content by mirs

That answers my question actually, sorry I was unclear. Thank you for your help!

Thank you! One last question -- if the uncertainty for measuring the diameter is ± 0.00001 m, how would that change in the inverse square of the diameter? I would think to convert the absolute uncertainty to a relative uncertainty; i.e. 0.0008 ± 0.00001 m would be 0.0008 m ± 1.25 %, and then...

Considering the diameter is measured to 2 sig figs, the slope should have 2 as well, right?

EDIT -- Wait, the slope does not give me p! I need to solve for p, since that is 4pL/pi and sub in the given value for L. Oops.

OK, will do, thank you. I am now comparing my experimental value with the theoretical value. The slope is 2x10^-5, so I worked out the following: |[(1.18 x 10^-6 ohm*m) - (2 x 10^-5 ohm*m)]/(1.18 x 10^-6 ohm*m)| x 100 = 1595 % That is huge! I worked it out a couple of times and I can't seem to...

I don't think we are required to add error bars but is it better to include them? Thanks again! :smile:

Does this look ok?

Perfect. Thank you for all your help!

That looks more like it... thank you so much for your help!

Sorry, you're right, it is over 4, not *4

Basically my graph is throwing me off since it's not linear. Would it be incorrect if I take the most linear portion of the graph and calculate the slope manually from there, instead of adding a trendline and having excel do it?

Homework Statement We were given five samples of nichrome wire, each with a different diameter but the same length. A micrometer was used to measure the diameters. We then measured and recorded the electrical resistance, R in Ohms of each nichrome sample with a DMM. I will try to summarize all...

OK, so I'm guessing I don't plug t into the energy equation in the first place? because I did that and found the derivative to be 5ktv^4

Yes! I meant (kdv^5)/(v−v0).

Homework Statement A biologist determines experimentally that the number of calories burned by a salmon swimming a distance d in miles upstream against a current v0 in miles per hour is given by Energy = kdv^5/v − v0 where v is the salmon’s swimming speed relative to the water it is in...