Recent content by mitchy16

Thank you for the reply. By air gap I mean once I was done sucking the liquid, in the tip, there was fluid then like an “air bubble” then fluid again. The point of the experiment was to see if our micropipetting techniquie was accurate since its our first time. Is it safe for me to say I was...

Thanks for the reply. Yes, it is my first time using these pipettes, we just learned how to use them. The point of the experiment was to learn good technique and see if we were accurate. I did do it twice, the first I had an air gap and second time I did not. A few of my friends had air gaps as...

Used a P100 to pipette 93.6 micro-litres of fluid. There was an air gap in the pipette tip the first time I did it but no air gap the second time. I'm assuming there shouldn't be an air gap but can somebody tell me for sure?

Yes! Thank you, I realize my mistakes now! I retried and it worked out, I appreciate the help!

Homework Statement Suppose a double-slit experiment is immersed in water (with an index of refraction of 1.33). When in the water, what happens to the interference fringes? Homework Equations λ = λ0 / n y = (λmL) / d d = distance between slits L = distance to viewing screen n = index of...

Yes, human ears were used to hear the loudest volume. The tube was approx. 1 metre long and the diameter was approx. 10cm. The bottom of the tube was closed, and the top was open. There were 4 different frequencies tested, 400, 800, 1200, 1600, 2000 Hz. Also, it was assumed that it was the first...

Homework Statement Determine sources of error which could have affected the results. Some background information: The lab consisted of playing a tone generated by a tone generator above a standing open-closed tube which had water in it. The first harmonic was measured through a computer system...

OH, I understand my mistake now! Thank you so much, that clears it up.

Yes, I had tried relating to Newton's Third Law, and that part makes sense, but if I were to solve for force, would it not be: Wire A: F = (L)(2I) X (B) 1/2F = (L)(I) X (B) Wire B: F = (L)(I) X (B) I think I'm just missing something obvious, but I'm not sure what. Thanks!

Homework Statement Two parallel wires have currents that have the same direction, but differing magnitude. The current in wire A is I, and the current in wire B is 2I. Which one of the following statements concerning the situation is true? A) Both wires attract each other with the same force...

Okay, so, just for clarification would they attract? Which would produce a larger magnetic field?

Thank you so much!

The radius of loops is 10.5cm, distance between is 15cm, and distance to was 20cm? I am not sure what else I'm missing, sorry I'm a bit confused! Would it be the following? https://www.physicsforums.com/file:///C:/Users/rajinder/AppData/Local/Temp/msohtmlclip1/01/clip_image002.png I have...

Thank you for your help! I understand the graphing part and graphed it as you had stated but does that mean I don't have to use the formula they have provided?

As in the magnetic field wraps around the current carrying coil? Yes. And no, sorry, there is no figure with this problem. It pertains to a lab, and in the lab the radius of the two coils was 10.5cm and they were approximately 15cm apart, if that helps any! Thank you!