- #1
mitchy16
- 23
- 2
Homework Statement
Suppose a double-slit experiment is immersed in water (with an index of refraction of 1.33). When in the water, what happens to the interference fringes?
Homework Equations
λ = λ0 / n
y = (λmL) / d
d = distance between slits
L = distance to viewing screen
n = index of refraction
The Attempt at a Solution
So the wavelength in the water would be:
λwater = λair / 1.33
1.33λwater = λair
And then:
ywater = ( (m) (1.33λwater) (L) / d )
The answer is supposedly they will be more closely spaced, but I am not sure why that is correct because wouldn't the distance be 1.33 times that of the original distance?