Recent content by Mohammad

let k = lcm(n1, n2) which is the lowest common multiplier x(n+k) = x1(n+k) + x2(n+k) Since k is the lowest common multiplier, that means that it will satisfy the requirement for both signals (for example: x1(n+2) = x1(n+4) = x1(n+6) = ... ). So you have x(n+k) = x1(n) + x2(n)

Hi everyone, I have been recently intrigued by a seemingly simple problem: How to compare the averages of two groups with different sizes. For example: Suppose you have a driver A who wins 100 out of 200 races, and a driver B who wins 1 out 2 races. It is clear that although the average is...

Thank you for your reply. I can understand what is going on now. I was basically mixing up the acceleration relative to the ground with the acceleration relative to the center of mass.

Hi, this is my first post :) I have a question in reference to the same problem in: https://www.physicsforums.com/showthread.php?t=67697&highlight=Falling+Mass I am having trouble comprehending the 3rd part. I understand that the differential equation to solve is: m\frac{d^2y}{dt} +...