- #1

Mohammad

- 4

- 0

I have a question in reference to the same problem in: https://www.physicsforums.com/showthread.php?t=67697&highlight=Falling+Mass

I am having trouble comprehending the 3rd part.

I understand that the differential equation to solve is:

[tex]m\frac{d^2y}{dt} + 2ky = mg[/tex]

Solving this equation yields the following complete solution:

[tex]z(t) = \frac{mg}{2k} + c_1cos(\sqrt{2k/m}t) + c_2sin(\sqrt{2k/m}t)[/tex]

I am stuck at this point. The solution the author posted in the above-mentioned topic doesn't seem coherent to me from a mathematical point of view. Any guidance would be appretiated.