Prove the sum of 2 signals is periodic?

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If two discrete signals, x1[n] and x2[n], are individually periodic, their sum is also periodic. The periodicity condition requires that x[n+N] = x[n] for integers n and N. The lowest common multiple (LCM) of their periods, denoted as k, ensures that both signals align at this interval. Therefore, at n+k, both x1 and x2 will repeat, confirming the periodicity of their sum. This demonstrates that the sum of two periodic signals remains periodic.
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hey guys - just a question regarding a systems and signals course:

if I've got two disctrete signals: x1[n] and x2[n]

if i know both signals are periodic (individually) how do i prove the sum of these signals is periodic?

requirement for periodicty (one signal): x[n+N] = x[n]

where n and N are integers - remeber - discrete signals!

thanks!

John
 
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Lcm (n1,n2)
 
Last edited:
EvLer >> Please elaborate...lowest common multiple of n1 and n2? not entirely sure what you mean ..thanks...
 
let k = lcm(n1, n2) which is the lowest common multiplier

x(n+k) = x1(n+k) + x2(n+k)

Since k is the lowest common multiplier, that means that it will satisfy the requirement for both signals (for example: x1(n+2) = x1(n+4) = x1(n+6) = ... ). So you have

x(n+k) = x1(n) + x2(n)
 
Thanks Mohammad!

John
 
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