neilparker62's latest activity

I am very sorry, Robert, to hear about his passing. He was a valued member of this community, widely appreciated for his thorough...

Deepest condolences - Robert to you and all the family. It's been an honour to share this forum with stalwarts such as your Dad. We'll...

Good afternoon, This is not Paul, but rather his son Robert. I am very sad to write here that my dad passed away on Saturday...

It's the end of the year and once again I wish to thank the mentors and admins for their stedfast commitment to the PF cause and for...

Seconded. And if I may put it this way - it's reward enough to be part of the PF community and (occasionally) to post something that...

@PeroK . Stop complaining about AI - you're better by far!

If I am understanding you, what you really need is a motorized mount, not necessarily a longer focal length lens. In order to use...

Yes - as mentioned above the technique is strikingly similar to that employed in Diophantus II VIII which is "to divide a square into...

Perhaps worth noting (in retrospect) that you will get this equation directly by implementation of @GiorgioPastore 's suggestion in post...

As others have noted, if the four sides of that quadrilateral have lengths a, x, b, and the diameter 2x, then 3x^2 = a^2+ab+b^2. As to...

I think I figured out now what @daverusin did in post 41. One begins with ## x^2+xy+y^2-3=0 ##, and to find the rational solutions...

Definitely the most efficient solution!

Most of his posts were on topics way beyond my 'ken' but I will remember him as a very clued up 'no nonsense' physicist. Here's a very...

I think the simplest way to get the result is by using the triangle with sides 2, 11, and AB in the modified figure below. The length of...

or ##RL^2 = (2x)^2 - (2)^2 = 4x^2-4## We can also draw the other diagonal and apply Ptolemy directly: ##2x + 22x =...