Recent content by Nick O

No problem! I'm glad that helped, because I haven't used phasors since learning them a few semesters ago, and I wouldn't have been able to make many more useful observations in my sleep-deprived state [emoji14]

It's like counting people with your fingers; you are representing each person with a finger, because math works similarly for both fingers and people, but fingers are more convenient. Or maybe I should sleep.

For a rigorous proof, we need a precise question. The units of P_0 are clearly volts, so that much is self-evident. It is also evident that if V_0=Re[P_0e^{jwt}] and V_1=Re[P_1e^{jwt}], then V_0+V_1=Re[P_0e^{jwt}]+ Re[P_1e^{jwt}]=Re[(P_0+P_1)e^{jwt}]. What do you want to prove?

They do not represent the same quantity, even though they represent the same concept. It is an error to equate both to V; my book used v (lower case) for the time-domain value, and V (capital) for the phasor (or "frequency") domain value. The units are the same, but the values are not! The...

Never mind, my coffee must have been spiked or something. There is no imaginary number in the second wave function.

I can't add this to my previous post through Tapatalk. Sorry!

Edit: I forgot to add the picture, and I'm having trouble adding it from Tapatalk. I'll add it soon. I'm trying to understand the derivation in my textbook of the wave function for a potential step. The derivation reaches the step shown in the attached photo, which I am fine with. However, the...

You mean the definition Drakkith posted? I'm not seeing how that conclusion logically follows from the definition...

Ah, I guess I had no idea what kind of output an accelerometer produces. I thought that 0 would also be the "rest" value, resulting in no net change when falling.

Really? I thought laptops and the like used accelerometers to detect falling motion in order to move the read/write head from the hard disk drive. Edit: then again, it makes sense that they would read zero... so some special mechanism is probably used in this case.

I just skimmed through the answers and didn't see a comment like this. I'm sorry if I missed it and am just repeating what someone else said. You can safely think of an antiderivative as exactly what the name says: the inverse of a derivative. d/dx 5 = 0. So, the antiderivative of 0 dx has to...

Thank you all for your responses! So, to sum up: There could be some accumulated quantum fluctuations to cause such a thing, but we can't be sure because we don't even know how gravity figures into quantum mechanics. But, even if it can be caused by quantum interactions, it is much more likely...

My question will probably be enough to make this obvious, but I should start by saying that I have not formally studied quantum mechanics, and I know little more about it than the wave equation as a function of x and t. Does the inherently probabilistic nature of quantum mechanics have some...

It's kind of like GPE, but the wires essentially don't exist. The energy doesn't change until you pass through a non-wire element. It's worth noting that the connections on a schematic are just there to show us how the elements are related. The actual wiring of a physical circuit need not look...

Is the force applied during the "squat" constant? My gut tells me that it's probably linear, but not constant. My gut has been known to lie on occasion, though. Edit: Actually, linear force would necessitate two discontinuities: one at the start of application, and one at the end. It's...