Recent content by Noman Rasheed

Makes sense. Thank you so much!

Hello, My university is offering a couple of programs in Physics: Applied, Astro, Computational, and Material. So far, I liked Material and Applied in terms of getting early job opportunities. What advise do you guys have for me, before I make my mind for any of them? Thank you!

I can't find out work done, since I don't have the value of K. I can figure out K, but I just don't know whether I use p2 or p1 in the formula.

Volume is constant.

I am so confused right now. I have the value of ϒ, which is 1.4. I can also use formula: pVϒ = K, but I don't know which p should I use. As, I come up with values for pressure. Further, work done could be found out by K(Vf1-ϒ - Vi1-ϒ)/(1-ϒ). Still I don't know how to find the value of K.

The first law of the thermodynamics says that the change in internal energy = heat added to the system - work done by the system. However, I can't connect the dots with the final temperature based on this definition. Any hints please?

So, there is a problem given, where diatomic ideal gas N2 is involved. Both blocks have same volume: 1m3. The molar mass of gas is: 28 g/mol. Initial temperature is 300K. I need to find ΔS and PF. First, I did find P1 by using formula: PV = nRT so, P1 = 1*8.3145*300/1 = 2494.35 Pa and P2 =...

Typo. I got it. Thank you so much!

I got it. Thank you so much! Oh! That mean's a normal force of 4.30 N which is acting in the upward direction stops the meter stick, which is carrying masses, from falling downward. Am I right?

There is pressure, and I guess torque too, which was calculated as 0 ± 0.003 Nm.

Yes, that's what I was saying that sum of T and sum of F (separately) should be zero. If the normal force can't be, then what is that 4.31 N representing? Does it say that "4.31 N" of weight is acting downward (due to gravity)?

Force and Torque. Apologize!

Because sum of F and T should be 0 for being in equilibrium. Right?

∑FN = m*g*cosΘ , where Θ = 0° ∑m = 0.1 + 0.07 + 0.075 + 0.06 + 0.1342 = 0.4392 kg ∑FN = 0.4392 * 9.8 = 4.30 N This time I used the experimental mass of the stick, my bad for the last time. Shouldn't the normal force be zero actually?

Here it is: