Recent content by .NoStyle

Homework Statement How come a bouncing ball does not exhibit SHM characteristics? Homework Equations no clue The Attempt at a Solution When I think of SHM, I don't think of contact forces. In the bouncing call case, there is a contact force present when the ball hits the...

Wow, thanks a lot for explaining that clearly dynamicsolo, I appreciate it! That's helpful to know. :)

ok thanks everyone for your help. I appreciate it.

I'm a bit confused with steps 1 and 2 since there are many names for the same thing. First off, what do you mean "gravitational force" is that the same thing as Fg = Gm1m2/r^2??and with what you're saying, we don't need to know the mass of the satellite therefore: Fg= GMe/r^2 ? and then...

Hi Dynamicsolo, yes it is 8.7E-1 m/s^2 this is what I did. I used the formula asubr = omegasquared*radius i found the requency and plugged that into the equation arrived with that answer. The problem is, I don't know if I did it 100% correctly. I'll try your method and report back...

hmmm i needed help with that, I got 8.7E-1 meters/secondthat's wrong huh? thanks

hey dynamic, once again, thanks a lot for the help. I got it right I think! 1.039E7 meters! hehehe

hi dynamic, the circumference is 2pi*radius but we don't know the radius. So I have2pi*radius/6hours = sqrtof(GMe/r) solving for r I get:r ^1.5 = sqrt of (GMe) * 6 all over 2pioh god, what am I doing?

The distance is 2pi, isn't that right? so 2pi/6h?

Thank you. So for V, that would be 2pi/6h?

Hi again dynamic solo, thanks for all the help lately. Before I go further, r in the "circular velocity" equation is the radius of earth? thanks

would it be the Universal Gravitational Constant? Sorry, I'm not really clear with what you're saying. Thanks

Homework Statement A spy satellite is in circular orbit around Earth. It makes one revolution in 6.00 h. A. How high above Earth's surface is the satellite? B. What is the satellite's acceleration? Homework Equations I'm not sure but I believe we could possibly derive...

thanks dynamicsolo!

ok thanks guys, so fs is the frictional force I'm looking for. I understand now!dynamicsolo, so when it asks, "Does the frictional force necessarily have magnitude μsN? Explain." so fs,max = μsN sorry if I'm being redundant, but it seems like you're confirming that you don't need to be at...