A spy satellite is in circular orbit around Earth. It makes one revolution in 6.00 h.
A. How high above Earth's surface is the satellite?
B. What is the satellite's acceleration?
I'm not sure but I believe we could possibly derive something from
SUMofF = (Gm1m2)/r^2
and with NSL, v=sqrtof (GMe/r)
where Me is the mass of the Earth 5.974e24 kg. G is the universal gravitational constant 6.67e-11N * m^2/kg^2
The Attempt at a Solution
and r is the radius of the earth plus the radius of the height. So we can find the height that the satellite is by deducting the radius of the earth (6.371e6 m) from r to find the height.
I don't know what equation to use and I don't know how I would find the acceleration.
Thanks for your help!