Recent content by odolwa99

From the books example, |k| was shown as a separate line drawn to the x-axis, but equal to the radius length of |ac|. That particular example makes reference to the circle touching the x-axis, and I think the purpose of |k| was to connect a radial line to the axis and work it into the line...

The example in the textbook makes use of the equation for a circle, (h-x)^2+(y-k)^2=r^2. They define the centre of the circle (h, k) and the radius = |k| = |ac|. So, without (h, k), one of the 2 points of contact with the circle (I went with (-3, 0)) is subbed into the equation in order to try...

With this question, I have worked out the correct answers (see the section bordered by BBB), but my original approach was to go by the 1st attempt (bordered by AAA). In the 1st attempt, the h/ k equation results in a single centre, rather than the 2 required to form the 2 separate circle...

Ok, I have it now. Thank you very much.

I'm having some difficulty with this question. Can anyone help me out, please? Many thanks. Homework Statement A circle of radius length \sqrt{20} contains the point (-1, 3). Its centre lies on the line x + y = 0. Find the equations of the 2 circles that satisfy these conditions...

Ok, so the book is definitely wrong? Thanks.

In Q.1 The arrangement is P(S, F, F) + P(F, S, F) + P(F, F, S). Where F is fail, i.e. not the selected day, so 6/7. And S is success, i.e. the selected day, so 1/7. Then multiply the success as shown in the 1st sentence and add the 3 totals for the answer. The same logic applies with...

Homework Statement In order to highlight the problem I'm having here I have posted two questions, the answer for the second matches the textbook answer, the first does not. The wording of both questions appears to be the same. Have I gone wrong in the 1st question, or is the book incorrect...

Great. Thank you very much.

Homework Statement Just a quick question. In the attached image, I can say \vec{am}=\vec{c}-\frac{1}{2}\vec{a}. Although subtraction is not commutative, can I also say (relative strictly to vectors) that \vec{am}=-\frac{1}{2}\vec{a}+\vec{c}, considering \vec{am}=\frac{1}{2}\vec{ao}+\vec{c}...

Thank you.

My answer is almost correct, except for the negative sign. Can anyone help? Many thanks. Homework Statement Q. Without using a calculator, show that \sin10^{\circ}+\sin80^{\circ}=\sqrt{2}\cos35^o Homework Equations The Attempt at a Solution...

Looks like I was over-thinking this. Ok, thank you.

In the final proof, I have \frac{h-h\tan B}{\tan B}, rather than \frac{h-h\tan B}{1+\tan B}. Can anyone help me out? Many thanks. Homework Statement In the triangle pqr (see attachment), |\angle qrp|=90^{\circ} & |rp| = h. s is a point on [qr] such that |\angle spq|=2B & |\angle...

Ok, thank you. I'll give that a 2nd look.