Recent content by onurbeyaz

Thanks for the answer

If the answer is yes, can I dissolve all the ethanol that exists in a cup of water

"The extent of solubility ranges widely, from infinitely soluble (without limit) (fully miscible[1]) such as ethanol in water, to poorly soluble, such as silver chloride in water." from wiki page of solubility So does it mean that you can solve ethanol in water as much as you want? Even if...

If one atomic mass unit is 1/12 of a C-12 atom, so 1 amu must be; 1 Amu = 1/2 ( Mass of proton + Mass of neutron + Mass of electron ) But the equation gives the answers that 1 amu is 1,6737 10^(-27) kg, which is different than the internet says I am using very sensitive values for the...

And how did they found the numbers of electrons

Ok, so only the number of protons will be enough too. In other words, how did they know the number of protons in elements when they were forming the periodical table?

How can I find the number of protons and neutrons of any element without looking the periodic table. And I need them each so mass spectrometer won't work Edit: I noticed that my title is wrong, explanation of the number of electrons are not needed

Thanks for the answers. So if the colliding electrons energy is enough, the +1 ion can loose one more electron (even if its very unlikely). And what about the first question? When and how did the explanation of canal rays discovered?

Even a guess is really appreciated

Any answer?

I know how the canal rays are produced. As I looked from wikipedia; "The process by which anode rays are formed in a gas discharge anode ray tube is as follows. When the high voltage is applied to the tube, its electric field accelerates the small number of ions (electrically charged atoms)...

Assume that I have a sample of an element which is electrically neutral, I want to know the number of protons, and neutrons in atoms of this element. What kind of experiment should I do? In other words, how did they know the number of protons and neutrons of elements when they were forming the...

Thanks for the answer. I don't know any of the nuclear physics so this is much more than I expected. Is this why Rutherford used Gold in his experiment? What will happen if we use any other material such as any other metal like iron, or non metal like carbon

Thanks for the answer, so can we say that it is because the strenght of coulomb force in this situation is usually higher than atomic bounds in Be, but lower than atomic bounds in Au(I even don't know if bounds are more strenght in Au than Be)

Why do alpha ray tear out neutron in Be, but don't do such thing in Au?