Recent content by patzer234

For your momentum equation there is initially only one velocity, 4.3 metres per second along the positive x-axis ( try drawing a sketch here as velocity is a vector and direction will affect the sign of the value of the velocity), so it should be written ## \left(m_1+m_2\right) v_i ## on your...

It's good to hear that you are looking forward to learning quantum mechanics; I think secretly every physics student does. It seems that you have the work ethic to study but if you haven't already you should search for studying techniques to improve your grades/ understanding. Also you said that...

You have the first part correct i.e. ##E=hf## (read about the photoelectric effect for more details on where this comes from). For the second part what do you think happens when the temperature is reduced? Does quantum physics have any role to play in this? Do you know any quantum physics...

Where the factor of 2 comes from still puzzles me as in one of your posts the 2 is already outside the integral before you integrate the function.Therefore how can it come from the limits of integration? Also,I sketched the ##\vec r## equation and attempted to understand it geometrically but I...

That would be great to see a sketch showing why ##dl= r~dθ/cosθ## is true as I don't know how it is derived. With respect to the question, I keep getting ## \frac {k_e λ} {d} sinθ_o## as my answer which is annoying as I am only off by a factor of 2. I used the trig relation that I mentioned in...

I have the following expression for the integral after using ##r=l~\hat x + d~\hat y## : ##\vec E= k_e~λ∫\frac {dl}{r^2} \frac {l~\hat x + d~\hat y}{\left| r\right|}## Then using L/2 and -L/2 as bounds and separating the x and y component integrals I noticed that the x integral equals zero...

I'm still struggling with ##\mathbf r## and what variables it corresponds to. To try to solve this I looked at the textbook examples(Ex 23.7 The Electric Field due to a Charged Rod) and in it they say that vectors do not need to be handled due to the sum of the rod's contributions all being in...

Well I know that ##\hat {\mathbf r}=\frac{\mathbf r}{\left|r\right|}## but I don't know how ##\hat{\mathbf r}## is related to ##l##. However I guess there must be a way to connect ##\hat{\mathbf r}## and ##l## as implied by your question but it escapes me at the moment.

Homework Statement (Taken from Serway and Jewett Chapter 23, Q44, 9th Edition) A thin rod of length ## l ## and uniform charge per unit length ##λ## lies along the x-axis as shown in the image attached. (a) Show that the electric field at P, a distance d from the rod along its perpendicular...