Recent content by paytona

Using your formula I got .568 m/s^2... Does that sound right?

Wouldn't the angle being used be -25* rather than positive??

Homework Statement The 20.0 kg box is being pushed with a 45.0N Force acting at an angle of 25.0*. The coefficient of kinetic friction on this surface is 0.150. Find the acceleration Homework Equations F=ma Fy=0 Fx=0 The Attempt at a Solution So I attempted this so far (sum)Fy=0 Py+Fn-Fg=0...

Because I am missing direction. I feel I should use the voltage I get from solving for V as EMF to solve for velocity. I'm just very unsure about the actual EMF step and if the direction would be to right because the number is positive.

Homework Statement A 425 mA conventional current is induced in a 48.0cm wire moved through a magnetic field. A 11.5 Ω resistor is connected to the wire as shown in the diagram below. If the magnetic force acting on the wire is 323 mN, then determine the direction and magnitude of the velocity...

So then to calculate the net force at the center of the square I've taken half of the distance I had for the charge of q1 -> q4 = 25.738684 / 2 = 12.869342cm So to calculate the center force I used the formula Fnet= |Kq1q2|/r2 once for the left side and once for the right side of the square...

Yes the charge on q4 due to the other 3. So I would use F=qE to calculate the net force on it right? It just seems wrong because the direction would be north east?

Solution?? Ok so this is what I did → Using pythagoreon theorem I found the length of the diagonal line toward q4 which = 025738684 m I applied this to the previous calculation that I did wrong. But also, wouldn't the angle of q2 be 90° because it is a negative force and therefore repels...

do I square the distance anyway?

Homework Statement There are 4 charges in the corner of a square with the lengths of the sides measuring 18.2cm q1= 2.34μC (top left) q2=-1.58μC (top right) q3= 2.03μC (bottom left) q4= -3.00μC (bottom right) →Calculate net force on q4 →Calculate net force at the center of the square...

Homework Statement A 3.50kg block of wood is at rest on a 1.75-m high fencepost. When a 12.0g bullet is fired horizontally into the block, the block topples off the post and lands 1.25m away. What was the speed of the bullet immediately before the collision?The attempt at a solution d=1/2at^2...