- #1

paytona

- 11

- 0

## Homework Statement

There are 4 charges in the corner of a square with the lengths of the sides measuring 18.2cm

q1= 2.34μC (top left) q2=-1.58μC (top right) q3= 2.03μC (bottom left) q4= -3.00μC (bottom right)

→Calculate net force on q4

→Calculate net force at the center of the square

## Homework Equations

Fnet=|KQ|/r^2

K constant = 8.99x10^9

## The Attempt at a Solution

q1= [(8.99x10^9)(2.34x10^-6)]/(0.182)^2 = 635086.3422 @ 315°

q2= [(8.99x10^9)(1.58x10^-6)]/(0.182)^2 = 428818.9832 @270°

q3= [(8.99x10^9)(2.03x10^-6)]/(0.182)^2 = 550950.9721 @ 0°

for my next step I was going to calculate x and y components and then plug it into the

d=*sqrt [(x^2)+(y^2)]

to calculate net force on q4... but I'm very uncertain about how to continue or if my previous calculations are even right.