Well since C1 and C3 are in series, their total capacitance would be .75 microF. C2 and C4 would have capacitance .875, thus total capacitance for the system would be 1.625.
You have a 12V battery, times 1.625 total capacitance = 19.5 microcoulombs for the system (charge).
Now, voltage on...
Nevermind, I just figured it out - I was trying to use the individual capacitance of C2 and C3 when I should have been using the combined since they are in parallel. :)
1. The Question
a. What is the equivalent capacitance of the combination shown in the figure ?
b. If a 100V battery is connected across the combination, what is the charge on each capacitor?
c. What is the voltage across each?
2. Equations
C=Q/V, adding capacitance rules
3...