1. The Question a. What is the equivalent capacitance of the combination shown in the figure ? b. If a 100V battery is connected across the combination, what is the charge on each capacitor? c. What is the voltage across each? 2. Equations C=Q/V, adding capacitance rules 3. Solution attempt For part a, I added C2 and C3 to get .03, then added the two in series (1/.02)+(1/.03) and took the inverse to get a combination capacitance of .012 microF I am stuck on parts b and c, though. For B, we know Q=V/C and for C2 it would be Q=(100V)(0.01microfarads) which gives a charge of 1 microcoulomb. for C3 it would be Q=(100V)(.02microfarads)=2 microcoulombs. And for C1 it would be Q=(100V)(.02microF)= 2 microcoulombs. However this answer is not working. For part C, I tried plugging the charge and C in to the same equation to get the V back out, but again this has not worked. I'm not sure if my units are off, or if I am missing something conceptually.[/b] Any help would be appreciated!