Recent content by Pete5876

It's a complete code. Try pasting the code from my last post into https://www.onlinegdb.com/online_c++_compiler or any other IDE and the error comes out the same every time "main.cpp:12:16: error: reference to ‘negate’ is ambiguous".

#include <iostream> #include<vector> using namespace std; vector<int> negate (vector<int> a) { a.insert(a.begin(), -1); return a; } vector<vector<int>> negate (vector<vector<int>> a) { for (int i=0; i<a.size(); i++) a = negate(a[i]); // reference to 'negate' is ambiguous...

vector<OP> negate (vector<OP> a) { a.insert(a.begin(), neg); return a; } vector<vector<OP>> negate (vector<vector<OP>> a) { for (int i=0; i<a.size(); i++) a[i] = negate(a[i]); // reference to 'negate' is ambiguous? return a; } OP is an enum here. Why can't C++...

Hi. I wrote a little algorithm that calculates some physics equations for education purposes and it's in C++. I'd like to make it avaiable by creating a website and put that code in it so it either interprets the C++ code or preferrably works with an executable (but then how would it be...

I did and as you pointed out there is a substantial body of literature. I'm a slow reader and an even slower learner. We don't go by any textbook at uni and I have no idea what purification might possibly entail. After all, we're not tensor-crossing with any other space so tracing one space...

Show that this dephasing operation is Markovian $$E_t(\rho)=\left(\frac{1+e^{-t}}{2}\right)\rho + \left(\frac{1-e^{-t}}{2}\right)Z\rho Z$$ The operation is supposed to be Markovian when $$E_g E_h = E_{g+h}$$ So this is what I get when I apply this multiplication $$ E_g...

I'm trying to find the purification of this density matrix $$\rho=\cos^2\theta \ket{0}\bra{0} + \frac{\sin^2\theta}{2} \left(\ket{1}\bra{1} + \ket{2}\bra{2} \right) $$ So I think the state (the purification) we're looking for is such Psi that $$ \ket{\Psi}\bra{\Psi}=\rho $$ But I'm not...