Recent content by Physicslearner500039

I want to understand the direction of force on the voice coil, if the conductor is straight line it is easy to find the force direction. In the case of the diagram i shown below, for the curved surfaces i should take tangential to the surface at every point. Am i correct? So for position 1 since...

It is an example problem and i could understand the solution and the answers are ## R = \frac {V_{rms}^2} {P_{av} } = 9.6 \Omega## ##I_{rms} = \frac {P_{av}} {V_{rms}} = 12.5 A## ##p_{max} = VI = 2P_{av} = 3000 W## But main problem is the statement given by the author below the solution which...

When rotated 90 Degrees Is my understanding correct? Please advise.

emf = ##\frac {-N_{2} {d\phi}_{B2}} {dt}## ## M_{21} = \frac {{N_2}{\phi}_{B2}} {i_1}## are the equations This is the original position, now the coil 2 is moved so the axis is perpendicular. The flux ##{\phi}_{B2}## due to i1 is the amount of flux cutting the coil 2 due to change in current...

Just providing my thoughts, I am not sure if I am correct. You could probably take the result of standard solution of "Electric field on the axis of a ring of charge" and then integrating for the cone which will make things easy.

Thank you for clarifying and the videos are useful, but i have few doubts it will help if you can explain. In electric potential chapter i see the formula for electric potential for a point charge as ##V = \frac U q = \frac {q} {4\pi\epsilon 0 r}##. How to relate the above equation, in the...

I thought using Ohm's law ##V = I * R## and I am assuming that current is produced if we have voltage source ##V## and the circuit is having resistance ## R ##. So, probably there is a current source which can store current and does not require resistance to produce current. Am I correct?

I am not sure if i can explain my question properly. I am studying the Generators section in the magnetism chapter. As i mentioned the statement "The rate at which work is done is exactly equal to the rate at which energy is dissipated in the resistance". When the term dissipated is used does it...

Ok understood. Thank you, yes the formula i wrongly understood. The answer is ##B = \frac {10^{-7} * 6 * 8\vec j * (-\frac {1} {\sqrt2} \vec j + \frac {1} {\sqrt2} \vec k)} {0.05} ## ## B = 6.78\mu T \vec i##

The problem is simple, but have one confusion, if i substitute the values given, I get ## B = \frac {10^{-7}(6*10^{-6})[(8*10^6 \vec j) \times (-0.5\vec j + 0.5 \vec k)]} {r^2} ## ## B = 48\mu T\vec i## First thing the answer does not match. I don't see the angle in calculations between ##\vec...

I am not sure how i have done that mistake, the updated diagram is The horizontal components cancel out. The vertical component is for N turns ##-\int_0^{2\pi} NIRB\cos(30)d\theta## ##-\pi NIRB\sqrt3 = -0.443 \hat j N##

Surely a tough one, I am doing it from the basics. This is the diagram i tried to draw showing the Force and current I The Length L is the tangent to the circle. The Force F is pointing upwards at ##90 Deg## to the ##\vec B## and also perpendicular to ##\vec L##. I am considering a small...

Yes now i understand ##IBL\cos\theta = mg\sin\theta## ##I = \frac {mg\tan\theta} {BL}## Amps The ##mg ## component along the X-axis is 0. I got confused with that. Thank You.

I am struggling with the angles. Since the conducting wire is moving down for it to be stand still, the force should be opposing it, hence the current should be from Right to Left. I am confident of the Force direction and its value is if ## I ## is the current ##F = ILB (N)## since L and B...

I am not sure if i am correct a. On the sides of the rectangle the forces are equal and act along the same line of reference hence they cancel each other. b. The force on the lower side is ##F1=8.2*0.06*B = 0.492B## and the perpendicular distance is ##d = 8 sin(30)=4##. Hence the torque on the...